Specifying return rows in LINQ2DataSet
Asked Answered
M

1

1

I have a requirement to extract a distinct subset of rows from a DataTable, and thought LINQ2DataSets may be a useful and clean way to do this, however it appears that it is not possible to simply identify return rows from a LINQ2DS query as follows

var result = from r in fips.AsEnumerable() select
r.Field<string>("FACILITY_PROCESS_SUB_GROUP_CODE"),
r.Field<string>("PROCESS_SUB_GROUP_NAME"),
r.Field<string>("...

as I start getting errors after the first comma.

Is this a correct assumption, and how would I get around it to return a subset of columns from the dataset that I can apply a Distinct() method to?

Micrometeorology answered 14/11, 2008 at 1:30 Comment(0)
K
4

You forgot the new statement and field names:

var result = from r 
    in fips.AsEnumerable() 
    select new
    {
        FacProcess = r.Field<string>("FACILITY_PROCESS_SUB_GROUP_CODE"),
        GroupName = r.Field<string>("PROCESS_SUB_GROUP_NAME"),
        Item3 = r.Field<string>("Item3")
    };

You can also explicitly declare that you are going to use a type:

var result = from r 
    in fips.AsEnumerable() 
    select new MyType("InitClassParams") 
    {
        FacProcess = r.Field<string>("FACILITY_PROCESS_SUB_GROUP_CODE"),
        GroupName = r.Field<string>("PROCESS_SUB_GROUP_NAME"),
        Item3 = r.Field<string>("Item3")
    };

Scott Guthrie (VP Developer Devision, Microsoft) has some good info about LINQ (he talks about LINQ to SQL, but most of it applies regardless).

Then apply the distinct clause:

var result = from r 
    in fips.AsEnumerable() 
    select new
    {
        FacProcess = r.Field<string>("FACILITY_PROCESS_SUB_GROUP_CODE"),
        GroupName = r.Field<string>("PROCESS_SUB_GROUP_NAME"),
        Item3 = r.Field<string>("Item3")
    }
    distinct;

Then put it to a list or iterate over it. Nothing will be selected/distincted/etc until something like on of the following is run:

var list = result.ToList()
foreach(var item in result) {}
Kistner answered 14/11, 2008 at 1:39 Comment(0)

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