I created a bmp and I load it using SDL_LoadBMP
when inspecting the generated SDL_Surface
I can see it is of format SDL_PIXELFORMAT_INDEX8
.
I want to use the SDL surface to generate a texture using glTexImage2D
.
Normally I could just inspect the surface Something close to this:
SDL_Surface * surface = SDL_LoadBMP(filename.c_str());
GLenum mode = 0;
Uint8 bpp = surface->format->BytesPerPixel;
Uint32 rm = surface->format->Rmask;
if (bpp == 3 && rm == 0x000000ff) mode = GL_RGB;
if (bpp == 3 && rm == 0x00ff0000) mode = GL_BGR;
if (bpp == 4 && rm == 0x000000ff) mode = GL_RGBA;
if (bpp == 4 && rm == 0xff000000) mode = GL_BGRA;
GLsizei width = surface->w;
GLsizei height = surface->h;
GLenum format = mode;
GLvoid * pixels = surface->pixels;
/*insert gl texture magic*/
glTexImage2D(GL_TEXTURE_2D, 0, GL_RGBA, width, height, 0, format, GL_UNSIGNED_BYTE, pixels);
However SDL_PIXELFORMAT_INDEX8
has a BytesPerPixel
of 1 and all masks are 0. From the SDL Code Examples I read that: "A pixel format has either a palette or masks. If a palette is used Rmask, Gmask, Bmask, and Amask will be 0."
So I assume that my data has a palette instead of masks.
The glTexImage2D
states that it would only accept GL_ALPHA
, GL_RGB
, GL_RGBA
, GL_LUMINANCE
, and GL_LUMINANCE_ALPHA
.
Can I create a texture directly from any surface even if it is based on a palette?
Is there a way to use SDL to transform any Image into GL_RGBA
?
Am I missing an even better way?