Creating RPM from current directory

Question

I'm trying to create an rpm from local source. Is it possible to do compilation in a similar to what pdebuild does - just copy the local directory as the source and operate on that copy? Every time I do rpmbuild -ba ... it tries to unpack some archive in RPMBUILD/SOURCE, but I don't want to go that way.

Essentially I'd like to be able to just checkout the repository with the code, do rpmbuild -ba application.spec in that checkout directory and have it do the right thing... Is that possible?

Emend

Even now after years passed, you'd probable need to use --define to define the rpmbuild paths. – Kimberelykimberlee

Answer 1

I don't know about a better way than the following:

rpmbuild -bs my_file.spec --define "_sourcedir $PWD"

For my own project, I'm always using a Makefile to define make rpm once and then just use it.

Intern

Answer 2

The %setup macro in the spec file is what unpacks the source. Remove that, and your problem goes away, and you can do anything you'd like to fetch the source.

Destinee