I want to launch my VLC player through a Java program, can any one help me? Thanks in advance.
Launch VLC Player through Java
possible duplicate of how to control VLC by java –
Subjugate
Vlc is located on different places depending on your system, but this is for 64 bit
ProcessBuilder pb = new ProcessBuilder("C:\\Program Files (x86)\\VideoLAN\\VLC\\vlc.exe", "file to start with vlc");
Process start = pb.start();
and this should work for x86:
ProcessBuilder pb = new ProcessBuilder("C:\\Program Files\\VideoLAN\\VLC\\vlc.exe", "file to start with vlc");
Process start = pb.start();
backslashes (\) should be escaped: "C:\\Program Files\\VideoLAN\\VLC\\vlc.exe" –
Untouchable
ProcessBuilder pb = new ProcessBuilder("C://ProgramFiles/VideoLAN/VLC/vlc.exe", "D://avtar.mp4"); Process start = pb.start(); The Vlc player is opening for me but its not playing the video from the specified path. –
Zahavi
I am done with this problem the solution is something like this, you should paste the video file into yours workspace/yoursapplication/a.pm4 –
Zahavi
Vlc is located on different places depending on your system, but this is for 64 bit
ProcessBuilder pb = new ProcessBuilder("C:\\Program Files (x86)\\VideoLAN\\VLC\\vlc.exe", "file to start with vlc");
Process start = pb.start();
and this should work for x86:
ProcessBuilder pb = new ProcessBuilder("C:\\Program Files\\VideoLAN\\VLC\\vlc.exe", "file to start with vlc");
Process start = pb.start();
backslashes (\) should be escaped: "C:\\Program Files\\VideoLAN\\VLC\\vlc.exe" –
Untouchable
ProcessBuilder pb = new ProcessBuilder("C://ProgramFiles/VideoLAN/VLC/vlc.exe", "D://avtar.mp4"); Process start = pb.start(); The Vlc player is opening for me but its not playing the video from the specified path. –
Zahavi
I am done with this problem the solution is something like this, you should paste the video file into yours workspace/yoursapplication/a.pm4 –
Zahavi
You might want to try this sample of code:
Runtime.getRuntime().exec("path_to_your_VLC_exe");
Unfortunately you will need to have an absolute path to your executable file, which sometimes cannot be obtained.
Look here for more examples: http://www.rgagnon.com/javadetails/java-0014.html
You may want to obtain it from the user ;) –
Zany
public class Test {
public static void main(String[] args) throws IOException, InterruptedException {
Runtime.getRuntime().exec("\"E:\\Program Files\\VideoLAN\\VLC\\vlc.exe\"");
System.out.println("VLC started.");
}
}
It is unlikely that it is contained in E: –
Donothingism
What if i want to play a file with VLC ? –
Vervet
Usually, the first argument of any executable that works with files is the path of the file to open... for example: "vlc.exe MyVideo.mov" –
Untouchable
You'll need to specify an absolute path to the program, which might be a problem if you do not know where VLC is stored.
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