Diffrence between JRockit in BEA Weblogic and Sun Java Implementation

Question

We have different JRE implementation from 2 vendors one is Jrockit from BEA and other is from Sun. In my project the document clearly states to use the Jrockit implementation from BEA. So i want to know the differences and upperhand of Jrockit over the standard sun JVM.

thanks Punith

Goof

Answer 1

Firstly, BEA and Sun were both taken over by Oracle. So JRockit and HotSpot are now both Oracle products.

JRockit started out as a faster JVM than Hotspot for server-side code, but a lot of work has been done since then to make Hotspot faster, so it is not clear if that still applies. The other thing that I recall is that JRockit has (had) a different heap sizing strategy. In particular, you didn't need to provide a fixed upper bound for the heap. This could be a good thing or a bad thing, depending on your perspective.

From a purely functional stand-point, JRockit and HotSpot implementations of the same Java baseline should be virtually identical.

Here are some other resources (from a Google search):

• "Comparison Between Sun JDK And Oracle JRockit"
• JRockit JVM versus HotSpot JVM
• Wikipedia's JRockit page.

Feltner

Not sure about this answer, but Jrockit was used for the server side large applications. As u mentioned may be bcoz of the heap size strategy, And as both are in hands of oracle now need to watch as how they will trade with 2 some how similar products. – Goof

For instance, Java 7 Update 4 Release Notes gives some example of functionality reimplemented from JRockit. Seems that they will eventually merge them? Who knows... – Hanny

Answer 2

Technically they are both from Oracle now. ;)

Given most of the developers for the former Sun JVM are from the JRockit team, I suspect the difference will become smaller over time (i.e. there is only one development team for both products)

Inconsonant