Is std::string's default constructor no-throw?
Asked Answered
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Can std::string s; throw under any circumstances? Is this regulated by the standard (interested in C++03, in case there are differences)?

Tritanopia answered 20/1, 2013 at 2:41 Comment(2)
I don't have 03 handy, but in 11, the move constructor is the only one marked noexcept.Seasonal
I expected move constructors to be noexcept in C++11, and copy constructors to be allowed to throw for obvious reasons, but an empty constructor... I'm sure it can be special-cased to not allocate anything, but is it done like that is the question.Tritanopia
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This was changed by WG21/N4002. The first working paper contains it I see is WG21/N4296: // 21.4.2, construct/copy/destroy: basic_string() noexcept : basic_string(Allocator()) { }

Pablopabon answered 12/4, 2015 at 15:32 Comment(0)
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In C++11, the default constructor actually takes one (defaulted) argument, namely the allocator (21.4.2):

explicit basic_string(const Allocator& a = Allocator());

This constructor is not declared as noexcept. (I suppose that would require the allocator to have a non-throwing copy constructor.) As Jonathan and Bo point out, the allocator's copy constructor must not throw any exceptions, but the string's constructor is allowed to perform throwing operations (e.g. allocate an initial piece of memory). It should certainly be possible to write a string-like class that as a no-throw­ing, constexpr constructor, but the standard library string is not specified to be like that.

Meares answered 20/1, 2013 at 2:52 Comment(3)
The Allocator requirements say the allocator's copy constructor "shall not exit via an exception" and std::allocator's copy ctor is noexceptOverzealous
Hmmm. I followed what gets called during default construction and it turns out, the allocator's construction is throw(), and the rest basic_string() does is only to reinterpret a statically allocated array as an empty string. Only this reinterpretation part is not marked throw(), and everything else is. Can a reinterpret_cast throw?Tritanopia
The string constructor is allowed to allocate dynamic memory for the string. That could cause a bad_alloc. Most implementations don't, but you cannot formally rely on that.Hyo
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This was changed by WG21/N4002. The first working paper contains it I see is WG21/N4296: // 21.4.2, construct/copy/destroy: basic_string() noexcept : basic_string(Allocator()) { }

Pablopabon answered 12/4, 2015 at 15:32 Comment(0)
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Sure if allocation isn't possible for any reason it would throw

Jilolo answered 20/1, 2013 at 3:34 Comment(0)

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