Liferay ajax request and JSON response
Asked Answered
K

2

5

I am new in Liferay. I used service builder to create database. I populated them manually. And eventually I could call them in JSP using PersonLocalServiceUtil class. Now I want to use Ajax in my program.

For example: Person with attributes personID, personWeight, personTemperature and datetime are stored in database.

I want to do an ajax call by personID to see his weight or Temperature graph for particular timeline. All I know, I can call list from Database to controller But I don't know How can I convert it to JSON obejct and forward it to JSP upon request, so that JSP won't refresh the page but display new graph.

Kersey answered 19/7, 2013 at 11:25 Comment(0)
E
8

You can send person id from jsp using ajax request and you can fetch data inside controller(serveResource method) i.e

You need to create URL

<portlet:resourceURL var="resourceURL" >
</portlet:resourceURL>

Ajax Call

$.ajax({
  url : '${resourceURL}',
  data : data,//person id to sent
  type: 'POST',
  dataType : "json",
  success : function(data) {
    // get person data back from controller
  }
});

Controller part

public void serveResource(ResourceRequest resourceRequest, ResourceResponse resourceResponse) {

    //get person id using getparameter 

    JSONObject json = JSONFactoryUtil.createJSONObject();

    json.put("jsonData", "person details");
    response.getWriter().write(json.toString());

}

HTH

Eady answered 19/7, 2013 at 11:46 Comment(3)
Hi Before I close the answer, I just wanted to know one more issue. Why Service Builder is not generating JsonSerializer class ? And If It was generated, could I use it directly to response http requests in controller ??Kersey
Thanks Lucky Boy! This is completely covers very common scenario.Lalla
respond to http request with json object in portletObovoid
D
0
public void serveResource(ResourceRequest resourceRequest, ResourceResponse resourceResponse) {

    Map<String, Object> data = new HashMap<String, Object>();
    data.put("test1", "test1test1test1test1test1");

    super.writeJSON(request, response, new Gson().toJson(data));
}
Deceit answered 30/3, 2018 at 8:25 Comment(0)

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