Virtual constructor idiom and factory design

Question

In virtual constructor idiom there are virtual functions which returns new object OR copy of the object using virtual functions. But then to call these virtual functions polymorphic way, you must have object of that class created using actual constructor.

In design pattern context, it means client is aware of the type of object before using polymorphic way of object creation?

Araarab

Answer 1

The client doesn't necessarily have to be aware of the concrete type. For example, consider this hierarchy:

struct Base
{
    virtual ~Base();
    virtual Base * clone() const = 0;
    static Base * create(std::string const &);
    // ...
};

struct A : Base { A * clone() const { return new A(*this); } /* ... */ };
struct B : Base { B * clone() const { return new B(*this); } /* ... */ };
struct C : Base { C * clone() const { return new C(*this); } /* ... */ };

Base * Base::create(std::string const & id)
{
    if (id == "MakeA") return new A;
    else return new C;
};

In this case, the client can make and copy an existing object like so:

Base * p = Base::create("IWantB");  // or std::unique_ptr<Base> !
Base * q = p->clone();

In neither case does the client ever know the dynamic type of *p or *q.

Mcmann

Thanks @karrek, understood it now. Also it has cleared my another confusion about static method. The examples which i referred has either virtual function or static method. – Araarab

Answer 2

class Base
{
public:
    Base() { }

    virtual ~Base() { }

    // The "Virtual Constructor"
    static Base *Create(int id);

    // The "Virtual Copy Constructor"
    virtual Base *Clone() = 0;
};

Base *Base::Create(int id)
{

    if( id == 1 )
    {
        return new Derived1;
    }
}

class Derived1 : public Base
{
public:
    Derived1()
    {
        cout << "Derived1 created" << endl;
    }

    Derived1(const Derived1& rhs)
    {
        cout << "Derived1 created by deep copy" << endl;
    }

    ~Derived1()
    {
        cout << "~Derived1 destroyed" << endl;
    }

    Base *Clone()
    {
        return new Derived1(*this);
    }
};

Now in Main when you do

void main()
{
        cout << "Enter ID (1, 2 or 3): ";
        cin >> input;
        Base *pBase = Base::Create(input);
        Base *pCopy = CreateCopy(pBase);

        //Dont know what object is created but still access functions thru base pointer
}

Base *CreateCopy(Base *pBase)
{
  return pBase->Clone();
}

the client need not know the type of class it inherits but still call some function.

Brahmani

Answer 3

The virtual constructor idiom the client is not aware of the derived type. The whole purpose of this idiom is to enable cloning of an object through the base pointer. Here is an example:

class base
{
public:
   base* clone()
   {
       // NVI: implemented by derived classes.
       do_clone();
   }

 protected:
   virtual base* do_clone = 0;
};

class derived : public base
{
protected:
    virtual derived* do_clone()
    {
        // Implementation. Note the return value is not base*.
    }
 };

See this ACCU article for details: http://accu.org/index.php/journals/522

Jew

Nice, but the link is dead. – Dabbs

Answer 4

Eventually something somewhere has to know the concrete type of your objects. The idea of hiding that detail leads to a pattern called inversion of control or, more lately, dependency injection.

The thought is to nominate one component in the whole program which is aware of the concrete types used. It then becomes the responsibility of this component to assemble your object graph; other components take their dependencies as interfaces only, which are passed in on construction or through methods.

There are a handful of dependency injector implementations for C++: spring-cpp, autumnframework and dicpp come to mind. I've authored one myself, called sauce, which emulates the style of a java framework named guice.

Hostetler