Converting a Curl command to run in a Zapier Webhook
Asked Answered
O

1

5

I'm trying to find a way to run this curl command in the Webhook Zap on Zapier, but I can't seem to figure it out. How would I enter this in the Webhook? Would it be better to run it as a Code Zap?

curl -X POST "https://api.zoom.us/v2/users?access_token=eyJ0eXAiOiJKV1QiLCJhbGciOiJIUzI1NiJ9.eyJpc3MiOiJmY3FvTHlyRVRpR3VmWmw2dW1ZU2NBIiwiaWF0IjoxNTI4Njc0OTUxLCJleHAiOjE1Mjg2OTI5NTF9.fvDzS8-UtHyO_YUF5-eqLyuopAuoL48SRwKxcOV1YrE" -H "accept: application/json" -H "Content-Type: application/json" -d "{ \"action\": \"create\", \"user_info\": { \"email\": \"[email protected]\", \"type\": 1, \"first_name\": \"Chris\", \"last_name\": \"G\", \"password\": \"Test54321\" }}"
Ocarina answered 11/6, 2018 at 1:41 Comment(0)
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9

David here, from the Zapier Platform team. Luckily, this is an easy one. Since you're using nested data, you'll need to use Webhooks by Zapier's Custom Request. The setup is the following:

Body & URL: enter image description here

Headers: enter image description here

You can also do it through code, you'll have the same result.

Also, if that access_token is still live, make sure to revoke it now that it's been out in the public!

Dimitri answered 11/6, 2018 at 19:21 Comment(0)

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