Replacing tel or telprompt to call

Question

I've made an application is used to call predefined numbers upon button press. As far as i know the only way to make call inside app is to use "tel" or "telprompt". When i submitted an app i've received a rejection with this description:

2.5 Details

Your app uses or references the following non-public APIs, which is a violation of the App Store Review Guidelines:

teleprompt://

The use of non-public APIs is not permitted in the App Store because it can lead to a poor user experience should these APIs change.

For my first submission I used "telprompt" to call, then I changed it to "tel" because i read here that many apps were accepted with it and after second submission i received the same response with rejection. Can someone advice m how to use dial functions in app without "tel" or "telprompt"? Any help is appreciated, thanks!

upd: added text for second rejection

Hello,

Thank you for your resubmission. We noticed that your app still uses or references the teleprompt:// API, which is in violation of the App Store Review Guidelines.

We are unable to proceed with the review of your app until this issue has been addressed.

Going

Can you confirm that you received a rejection, exactly like the above, that referenced "tel:" as a non-public API? Note that it should be "tel:######" without any "//". The "tel:" scheme should be public. – Langdon

Yes, i copied it. And in my app I used 'tel://' with '//'. I assume this may cause error? – Going

tel:// is not meaningful. "/" is not a legal digit. – Langdon

Answer 1

From your update, it suggests you're sending tel://... or teleprompt://... as a URL. The tel: scheme takes a series of digits. / is not a digit, so there's no reason you should be passing that as part of the number.

Langdon

Answer 2

Use following code:

NSString *phoneNumber = @"[phone]";
NSString *phoneURLString = [NSString stringWithFormat:@"tel:%@", phoneNumber];
NSURL *phoneURL = [NSURL URLWithString:phoneURLString];
[[UIApplication sharedApplication] openURL:phoneURL];

This code is working for an app which I submitted to the Appstore.

Stralka

Yes, that's pretty much the same I use. But for some reasons Apple rejects my app for the second time. That's how i use it: NSString *number = [@"tel://" stringByAppendingString:current.phone]; [[UIApplication sharedApplication] openURL:[NSURL URLWithString:number]]; – Going

@dpaul93: use NSString *number = [@"tel:" stringByAppendingString:current.phone] i.e. don't add the two slashes. – Popup

Answer 3

You have used telEprompt:// instead of telprompt://

Landed