PHP, Get tomorrows date from date

Question

I have a PHP date in the form of 2013-01-22 and I want to get tomorrows date in the same format, so for example 2013-01-23.

How is this possible with PHP?

Steen

Answer 1

Use DateTime

$datetime = new DateTime('tomorrow');
echo $datetime->format('Y-m-d H:i:s');

Or:

$datetime = new DateTime('2013-01-22');
$datetime->modify('+1 day');
echo $datetime->format('Y-m-d H:i:s');

Or:

$datetime = new DateTime('2013-01-22');
$datetime->add(new DateInterval("P1D"));
echo $datetime->format('Y-m-d H:i:s');

Or in PHP 5.4+:

echo (new DateTime('2013-01-22'))->add(new DateInterval("P1D"))
                                 ->format('Y-m-d H:i:s');

Claptrap

This uses current, I need to pass in a given date. – Steen

Answer 2

 $tomorrow = date("Y-m-d", strtotime('tomorrow'));

or

  $tomorrow = date("Y-m-d", strtotime("+1 day"));

Help Link: STRTOTIME()

Dicarlo

I used this one and of all answers is the shortest and simplest version, thanks ! – Aleydis

This is cool and will also give you yesterday: -1 day – Hysterogenic

Answer 3

Since you tagged this with strtotime, you can use it with the +1 day modifier like so:

$tomorrow_timestamp = strtotime('+1 day', strtotime('2013-01-22'));

That said, it's a much better solution to use DateTime.

Chloral

Answer 4

<? php 

//1 Day = 24*60*60 = 86400

echo date("d-m-Y", time()+86400); 

?>

Logger

Note that this will fail in edge cases (daylight savings time). – Sudderth

This answer is wrong. I have a cronjob use this in a loop, and the system got died. – Hedjaz

Answer 5

echo date ('Y-m-d',strtotime('+1 day', strtotime($your_date)));

Bratcher

Answer 6

Use DateTime:

To get tomorrow from now :

$d = new DateTime('+1day');
$tomorrow = $d->format('d/m/Y h.i.s');
echo $tomorrow;

Results : 28/06/2017 08.13.20

To get tomorrow from a date :

$d = new DateTime('2017/06/10 08.16.35 +1day')
$tomorrow = $d->format('d/m/Y h.i.s');
echo $tomorrow;

Results : 11/06/2017 08.16.35

Hope it helps!

Bussard

Answer 7

/**
 * get tomorrow's date in the format requested, default to Y-m-d for MySQL (e.g. 2013-01-04)
 *
 * @param string
 *
 * @return string
 */
public static function getTomorrowsDate($format = 'Y-m-d')
{
    $date = new DateTime();
    $date->add(DateInterval::createFromDateString('tomorrow'));

    return $date->format($format);
}

Hege

Answer 8

By strange it can seem it works perfectly fine: date_create( '2016-02-01 + 1 day' );

echo date_create( $your_date . ' + 1 day' )->format( 'Y-m-d' );

Should do it

Cortez

Answer 9

here's working function

function plus_one_day($date){
 $date2 = formatDate4db($date);
 $date1 = str_replace('-', '/', $date2);
 $tomorrow = date('Y-m-d',strtotime($date1 . "+1 days"));
 return $tomorrow; }

Hamlani

what does the formatDate4db function do? Why replace the dashes with slashes in the string? – Emmuela

formatDate4db function pass the date and it make a format like database mysql format , and str_replace function , i have date format 2019/12/10 and replace with - – Hamlani

Answer 10

$date = '2013-01-22';
$time = strtotime($date) + 86400;
echo date('Y-m-d', $time);

Where 86400 is the # of seconds in a day.

Yazbak

No, one day doesn't always have 86400 seconds. – Greta

I don't get the problem. Please explain @Greta – Salesman

@Salesman days that make the switch to or from daylight saving time do not have 86400 seconds – Sosanna

I thought of that, DST is initiated at two o'clock and should therefore never result in a different date? – Salesman

The problem isn't daylight savings. Times in a database really should be stored as UTC which has no daylight saving time. If you're storing your dates in UTC this will work fine but is a bit obtuse. – Emmuela