auto-repeat flag in a pack format string

Question

In php, unpack() has the "*" flag which means "repeat this format until the end of input". For example, this prints 97, 98, 99

$str = "abc";
$b = unpack("c*", $str);
print_r($b);

Is there something like this in python? Of course, I can do

str = "abc"
print struct.unpack("b" * len(str), str)

but I'm wondering if there is a better way.

Jago

JBernardo, you should consider moving this to answer. – Canzonet

Possible duplicate of Unpack format characters in Python – Tivoli

Answer 1

There is no such facility built into struct.unpack, but it is possible to define such a function:

import struct

def unpack(fmt, astr):
    """
    Return struct.unpack(fmt, astr) with the optional single * in fmt replaced with
    the appropriate number, given the length of astr.
    """
    # https://mcmap.net/q/1922407/-auto-repeat-flag-in-a-pack-format-string
    try:
        return struct.unpack(fmt, astr)
    except struct.error:
        flen = struct.calcsize(fmt.replace('*', ''))
        alen = len(astr)
        idx = fmt.find('*')
        before_char = fmt[idx-1]
        n = (alen-flen)/struct.calcsize(before_char)+1
        fmt = ''.join((fmt[:idx-1], str(n), before_char, fmt[idx+1:]))
        return struct.unpack(fmt, astr)

print(unpack('b*','abc'))
# (97, 98, 99)

Troublemaker

Answer 2

In Python 3.4 and later, you can use the new function struct.iter_unpack.

struct.iter_unpack(fmt, buffer)

Iteratively unpack from the buffer buffer according to the format string fmt. This function returns an iterator which will read equally-sized chunks from the buffer until all its contents have been consumed. The buffer’s size in bytes must be a multiple of the size required by the format, as reflected by calcsize().

Each iteration yields a tuple as specified by the format string.

Let's say we want to unpack the array b'\x01\x02\x03'*3 with the repeating format string '<2sc' (2 characters followed by a single character, repeat until done).

With iter_unpack, you can do the following:

>>> import struct
>>> some_bytes = b'\x01\x02\x03'*3
>>> fmt = '<2sc'
>>> 
>>> tuple(struct.iter_unpack(fmt, some_bytes))
((b'\x01\x02', b'\x03'), (b'\x01\x02', b'\x03'), (b'\x01\x02', b'\x03'))

If you want to un-nest this result, you can do so with itertools.chain.from_iterable.

>>> from itertools import chain
>>> tuple(chain.from_iterable(struct.iter_unpack(fmt, some_bytes)))
(b'\x01\x02', b'\x03', b'\x01\x02', b'\x03', b'\x01\x02', b'\x03')

Of course, you could just employ a nested comprehension to do the same thing.

>>> tuple(x for subtuple in struct.iter_unpack(fmt, some_bytes) for x in subtuple)
(b'\x01\x02', b'\x03', b'\x01\x02', b'\x03', b'\x01\x02', b'\x03')

Ruwenzori