SoapHandler not called after WS operation is executed

Question

I have a servlet that also consumes SOAP WS (in doGet). I want to see SOAP envelope (or anything else in soap message). I adddd this code to my servlet class:

class ClientHandlerResolver implements HandlerResolver {
    public List<Handler> getHandlerChain(PortInfo port_info) {
        List<Handler> hchain = new ArrayList<Handler>();
        hchain.add(new TestHandler()); //  soap handler defined in TestHandler.java dumps messages to stdout
        return hchain;
    }
}

I a separate class, i have my TestHandler:

public class TestHandler implements SOAPHandler<SOAPMessageContext> {
private static final String LoggerName = "ClientSideLogger";
private Logger logger;
private final boolean log_p = true; // set to false to turn off 

public TestHandler() { 
logger = Logger.getLogger(LoggerName);
 }

public boolean handleMessage(SOAPMessageContext ctx) {
if (log_p) 
    logger.info("Test::handleMessage"); 

// Is this an outbound message, i.e., a request?
Boolean request_p = (Boolean)
      ctx.get(MessageContext.MESSAGE_OUTBOUND_PROPERTY);

// Manipulate the SOAP only if it's a request
  if (request_p) {
    try {
        SOAPMessage msg = ctx.getMessage(); 
        msg.writeTo(System.out);

    }
    catch(SOAPException e) 
    { System.err.println(e); 
    }
    catch(IOException e) 
    { System.err.println(e); 
    }
}
  return true; // continue down the chain

}

public boolean handleFault(SOAPMessageContext ctx) {
  return true; 

}

public Set<QName> getHeaders() { 
if (log_p)
    logger.info("getHeaders");
return null;

}

public void close(MessageContext messageContext) { 
if (log_p)
    logger.info("close");
}

}

Nothing is printed out when i make WS request. I don't even know if handler is called.

How to see printouts defined in Handler?

Bud

You haven't shown how you tie your handler resolver into service invocation. Do you use something like javax.xml.ws.Service.setHandlerResolver? – Stomatal

Hm, i don't have anything like that. Where should i put it, as a parameter to my webservice call? – Bud

What does the code look like for invoking the service? Do you use the Service class? – Stomatal

I just create MyService_ServiceLocator and MyService_Port objects and then call my operations on MyService_Port object like p.getApples(); All my code for WS client was generated from WSDL in Eclipse. – Bud

Aha, i found out that i should call setHandlerResolver() on my service object. Problem is there is no such method in my generated Eclipse generated classes. – Bud

Answer 1

I'm not sure what Eclipse is generating for you, but here's one way to do it. Assume MyService is the interface generated from the WSDL:

URL wsdlURL = new URL("...");
QName serviceName = new QName("...", "...");
Service service = Service.create(wsdlURL, serviceName);
HandlerResolver handlerResolver = new ClientHandlerResolver();
service.setHandlerResolver(handlerResolver);
MyService myService = service.getPort(MyService.class);
// invoke methods (operations) on myService

Stomatal

Eclipse generated code for Axis1 didn't allow me to setHandlerResolver. Then i used wsiimport tool from CLI (generates JAX-WS RI 2.1.6 in JDK 6 code) and now i am able to use handlers. – Bud