I have an issue using crypt() where if a user has a password (password1 in this example), and they change it to password2, the hashing returns the same result. You can test that here: OLD LINK Type password1 as current password, and password2 as new password and confirm password, you will see the results. If a completely non similar password is entered there is no problem. I understand there are other ways to go about hashing passwords etc. I'm more curious than anything. My code is below:
<?php
$oldpassword="password1";
echo "<form method=\"post\">
<p>Enter Current Password: <input type=\"password\" name=\"currentpassword\" /></p>
<p>Enter New Password: <input type=\"password\" name=\"password\" /></p>
<p>Confirm New Password: <input type=\"password\" name=\"confirmpassword\" /></p>
<p><input type=\"submit\" value=\"Change Password\"></p>
</form>";
$user_id = $_SESSION['user_id'];
$pass=$_POST['password'];
$salt = 'xxxxx';
$currentpassword = crypt($_POST['currentpassword'], $salt);
$oldpassword = crypt($oldpassword, $salt);
if(isset($_POST['password'])) {
if ($currentpassword !== $oldpassword) {
echo "The password you entered for current password does not match our records.";
}
else {
if ($_POST['password'] && $_POST['confirmpassword']) {
if ($_POST['password'] == $_POST['confirmpassword']) {
$hash = crypt($pass, $salt);
if ($hash == $currentpassword) {
echo "Current Password: ";
var_dump($_POST['currentpassword']);
echo "<br/>";
echo "New Password: ";
var_dump($_POST['password']);
echo "<br/>";
echo "New Hash: ";
var_dump($hash);
echo "<br/>";
echo "Current Password Hash: ";
var_dump($currentpassword);
echo "<br/>";
echo "<hr/>";
echo "Your new password cannot be the same as your current password.";
}
else {
echo "Your password has been changed successfully<br/>";
}
} else {
echo "Your passwords do not match. Please try again.";
}
}
}
}
?>
$salt = $username.$email_address;
$hash = sha1($pass.$salt);
Is this somewhat sufficient? – Amphitheaterxxxxx
as the salt. That is the problem. – Woolridge