I have a web server that has all of the configurations set in the code, but I want to be able to handle all page 404 errors. How would I go about doing this in Python?
Make a default handler in the root.
class Root:
def index(self):
return "Hello!"
index.exposed = True
def default(self, attr='abc'):
return "Page not Found!"
default.exposed = True
See also http://www.cherrypy.org/wiki/ErrorsAndExceptions#AnticipatedHTTPresponses if you want more traditional replacement of 4xx and 5xx output.
Make a default handler in the root.
class Root:
def index(self):
return "Hello!"
index.exposed = True
def default(self, attr='abc'):
return "Page not Found!"
default.exposed = True
Anticipated HTTP responses
The 'error_page' config namespace can be used to provide custom HTML output for
expected responses (like 404 Not Found). Supply a filename from which the output
will be read. The contents will be interpolated with the values %(status)s,
%(message)s, %(traceback)s, and %(version)s using plain old Python
string formatting <http://www.python.org/doc/2.6.4/library/stdtypes.html#string-formatting-operations>
_.
::
_cp_config = {'error_page.404': os.path.join(localDir, "static/index.html")}
Beginning in version 3.1, you may also provide a function or other callable as an error_page entry. It will be passed the same status, message, traceback and version arguments that are interpolated into templates::
def error_page_402(status, message, traceback, version):
return "Error %s - Well, I'm very sorry but you haven't paid!" % status
cherrypy.config.update({'error_page.402': error_page_402})
Also in 3.1, in addition to the numbered error codes, you may also supply "error_page.default" to handle all codes which do not have their own error_page entry
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