How do I link directories in python (Linux cmd ln -s equivalent)? [duplicate]

Question

I'm translating Linux commands to a python script. How would I perform the Linux command 'ln -s'

CMD:

    ln -s /users/me/link_file hello 

I want to link 'hello' to 'link_file' in python

Thanks!

Erleena

If you actually want to "perform the Linux command", see the subprocess module. If you want to create a symlink in the same way the Linux command does, see the os or pathlib module. – Montcalm

why don't you try it? – Bernardabernardi

Just want to make sure... Can't try it without knowing for sure because the environment is delicate. – Erleena

I think it is good to find the simple answer here on stackoverflow. The two questions are not the same... – Preciousprecipice

Answer 1

os.symlink() is the provided function for creating symlinks. They are created as such:

import os
os.symlink(src,dst)

Where src and dst are the paths.

See the documentation here for more info.

Bowse

"Create a symbolic link pointing to src named dst." – Preciousprecipice

The answer provided doesn't work if provided src path is relative - it creates broken link. Use following instead: import os os.symlink(os.path.abspath(src), dst) – Virgel