How to send a JSON object over Request with Android?
Asked Answered
F

8

116

I want to send the following JSON text

{"Email":"[email protected]","Password":"123456"}

to a web service and read the response. I know to how to read JSON. The problem is that the above JSON object must be sent in a variable name jason.

How can I do this from android? What are the steps such as creating request object, setting content headers, etc.

Farrington answered 12/6, 2010 at 0:57 Comment(0)
K
97

Android doesn't have special code for sending and receiving HTTP, you can use standard Java code. I'd recommend using the Apache HTTP client, which comes with Android. Here's a snippet of code I used to send an HTTP POST.

I don't understand what sending the object in a variable named "jason" has to do with anything. If you're not sure what exactly the server wants, consider writing a test program to send various strings to the server until you know what format it needs to be in.

int TIMEOUT_MILLISEC = 10000;  // = 10 seconds
String postMessage="{}"; //HERE_YOUR_POST_STRING.
HttpParams httpParams = new BasicHttpParams();
HttpConnectionParams.setConnectionTimeout(httpParams, TIMEOUT_MILLISEC);
HttpConnectionParams.setSoTimeout(httpParams, TIMEOUT_MILLISEC);
HttpClient client = new DefaultHttpClient(httpParams);

HttpPost request = new HttpPost(serverUrl);
request.setEntity(new ByteArrayEntity(
    postMessage.toString().getBytes("UTF8")));
HttpResponse response = client.execute(request);
Kessiah answered 12/6, 2010 at 2:17 Comment(1)
currently deprecated, unfortunately. :(Thereabout
P
155

Sending a json object from Android is easy if you use Apache HTTP Client. Here's a code sample on how to do it. You should create a new thread for network activities so as not to lock up the UI thread.

    protected void sendJson(final String email, final String pwd) {
        Thread t = new Thread() {

            public void run() {
                Looper.prepare(); //For Preparing Message Pool for the child Thread
                HttpClient client = new DefaultHttpClient();
                HttpConnectionParams.setConnectionTimeout(client.getParams(), 10000); //Timeout Limit
                HttpResponse response;
                JSONObject json = new JSONObject();

                try {
                    HttpPost post = new HttpPost(URL);
                    json.put("email", email);
                    json.put("password", pwd);
                    StringEntity se = new StringEntity( json.toString());  
                    se.setContentType(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));
                    post.setEntity(se);
                    response = client.execute(post);

                    /*Checking response */
                    if(response!=null){
                        InputStream in = response.getEntity().getContent(); //Get the data in the entity
                    }

                } catch(Exception e) {
                    e.printStackTrace();
                    createDialog("Error", "Cannot Estabilish Connection");
                }

                Looper.loop(); //Loop in the message queue
            }
        };

        t.start();      
    }

You could also use Google Gson to send and retrieve JSON.

Peanuts answered 12/6, 2010 at 7:40 Comment(4)
Hi could it be possible that the server requires me to set a header caled JSON and put the json content in that header ? I sending the url as HttpPost post=new HttpPost("abc.com/xyz/usersgetuserdetails"); But its saying invalid request error. The remiander of the code is the same. Secondly what does json = header = new JSONObject(); Whats happening hereFarrington
I'm not sure what kind of request is expected by the server. As for this ' json = header = new JSONObject(); ' it's just creating 2 json objects.Peanuts
@primpop - Is there any chance that you might be able to provide a simple php script to go along with this? I tried implementing your code, but I for the life of me could not get it to send anything other than NULL.Emf
you can get the output from inputsputstream(in object here) as string like this StringWriter writer = new StringWriter(); IOUtils.copy(in, writer, "UTF-8"); String theString = writer.toString();Jake
K
97

Android doesn't have special code for sending and receiving HTTP, you can use standard Java code. I'd recommend using the Apache HTTP client, which comes with Android. Here's a snippet of code I used to send an HTTP POST.

I don't understand what sending the object in a variable named "jason" has to do with anything. If you're not sure what exactly the server wants, consider writing a test program to send various strings to the server until you know what format it needs to be in.

int TIMEOUT_MILLISEC = 10000;  // = 10 seconds
String postMessage="{}"; //HERE_YOUR_POST_STRING.
HttpParams httpParams = new BasicHttpParams();
HttpConnectionParams.setConnectionTimeout(httpParams, TIMEOUT_MILLISEC);
HttpConnectionParams.setSoTimeout(httpParams, TIMEOUT_MILLISEC);
HttpClient client = new DefaultHttpClient(httpParams);

HttpPost request = new HttpPost(serverUrl);
request.setEntity(new ByteArrayEntity(
    postMessage.toString().getBytes("UTF8")));
HttpResponse response = client.execute(request);
Kessiah answered 12/6, 2010 at 2:17 Comment(1)
currently deprecated, unfortunately. :(Thereabout
T
35
public void postData(String url,JSONObject obj) {
    // Create a new HttpClient and Post Header

    HttpParams myParams = new BasicHttpParams();
    HttpConnectionParams.setConnectionTimeout(myParams, 10000);
    HttpConnectionParams.setSoTimeout(myParams, 10000);
    HttpClient httpclient = new DefaultHttpClient(myParams );
    String json=obj.toString();

    try {

        HttpPost httppost = new HttpPost(url.toString());
        httppost.setHeader("Content-type", "application/json");

        StringEntity se = new StringEntity(obj.toString()); 
        se.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));
        httppost.setEntity(se); 

        HttpResponse response = httpclient.execute(httppost);
        String temp = EntityUtils.toString(response.getEntity());
        Log.i("tag", temp);


    } catch (ClientProtocolException e) {

    } catch (IOException e) {
    }
}
Ta answered 22/2, 2012 at 6:32 Comment(0)
P
19

HttpPost is deprecated by Android Api Level 22. So, Use HttpUrlConnection for further.

public static String makeRequest(String uri, String json) {
    HttpURLConnection urlConnection;
    String url;
    String data = json;
    String result = null;
    try {
        //Connect 
        urlConnection = (HttpURLConnection) ((new URL(uri).openConnection()));
        urlConnection.setDoOutput(true);
        urlConnection.setRequestProperty("Content-Type", "application/json");
        urlConnection.setRequestProperty("Accept", "application/json");
        urlConnection.setRequestMethod("POST");
        urlConnection.connect();

        //Write
        OutputStream outputStream = urlConnection.getOutputStream();
        BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(outputStream, "UTF-8"));
        writer.write(data);
        writer.close();
        outputStream.close();

        //Read
        BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(urlConnection.getInputStream(), "UTF-8"));

        String line = null;
        StringBuilder sb = new StringBuilder();

        while ((line = bufferedReader.readLine()) != null) {
            sb.append(line);
        }

        bufferedReader.close();
        result = sb.toString();

    } catch (UnsupportedEncodingException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }
    return result;
}
Parfitt answered 24/5, 2015 at 18:3 Comment(0)
M
8

There's a surprisingly nice library for Android HTTP available at the link below:

http://loopj.com/android-async-http/

Simple requests are very easy:

AsyncHttpClient client = new AsyncHttpClient();
client.get("http://www.google.com", new AsyncHttpResponseHandler() {
    @Override
    public void onSuccess(String response) {
        System.out.println(response);
    }
});

To send JSON (credit to `voidberg' at https://github.com/loopj/android-async-http/issues/125):

// params is a JSONObject
StringEntity se = null;
try {
    se = new StringEntity(params.toString());
} catch (UnsupportedEncodingException e) {
    // handle exceptions properly!
}
se.setContentType(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));

client.post(null, "www.example.com/objects", se, "application/json", responseHandler);

It's all asynchronous, works well with Android and safe to call from your UI thread. The responseHandler will run on the same thread you created it from (typically, your UI thread). It even has a built-in resonseHandler for JSON, but I prefer to use google gson.

Mardellmarden answered 15/7, 2013 at 5:17 Comment(3)
Do you know the minimum sdk this runs on?Michelsen
I'd be surprised if it had a minimum since it's not GUI. Why not try it out and post your findings.Mardellmarden
Well i decided to use the native libraries instead. Theres more informatoin about that and since im fairly new to android. Im really a iOS dev. Its better since im reading up on all the docs instead of just plugging and playing with someone elses code. Thanks thoughMichelsen
C
3

Now since the HttpClient is deprecated the current working code is to use the HttpUrlConnection to create the connection and write the and read from the connection. But I preferred to use the Volley. This library is from android AOSP. I found very easy to use to make JsonObjectRequest or JsonArrayRequest

Caoutchouc answered 31/10, 2015 at 17:35 Comment(0)
L
2

Nothing could be simple than this. Use OkHttpLibrary

Create your json

JSONObject requestObject = new JSONObject();
requestObject.put("Email", email);
requestObject.put("Password", password);

and send it like this.

OkHttpClient client = new OkHttpClient();

RequestBody body = RequestBody.create(JSON, json);
Request request = new Request.Builder()
            .addHeader("Content-Type","application/json")
            .url(url)
            .post(requestObject.toString())
            .build();

okhttp3.Response response = client.newCall(request).execute();
Lawanda answered 22/3, 2016 at 17:13 Comment(1)
Upvoted for pointing to okhttp, which is a useful library, but the code as given does not help much. For example, what are the arguments passed to RequestBody.create()? See this link for more details: vogella.com/tutorials/JavaLibrary-OkHttp/article.htmlUndersexed
P
0
public class getUserProfile extends AsyncTask<Void, String, JSONArray> {
    JSONArray array;
    @Override
    protected JSONArray doInBackground(Void... params) {

        try {
            commonurl cu = new commonurl();
            String u = cu.geturl("tempshowusermain.php");
            URL url =new URL(u);
          //  URL url = new URL("http://192.168.225.35/jabber/tempshowusermain.php");
            HttpURLConnection httpURLConnection = (HttpURLConnection) url.openConnection();
            httpURLConnection.setRequestMethod("POST");
            httpURLConnection.setRequestProperty("Content-Type", "application/json");
            httpURLConnection.setRequestProperty("Accept", "application/json");
            httpURLConnection.setDoOutput(true);
            httpURLConnection.setRequestProperty("Connection", "Keep-Alive");
            httpURLConnection.setDoInput(true);
            httpURLConnection.connect();

            JSONObject jsonObject=new JSONObject();
            jsonObject.put("lid",lid);


            DataOutputStream outputStream = new DataOutputStream(httpURLConnection.getOutputStream());
            outputStream.write(jsonObject.toString().getBytes("UTF-8"));

            int code = httpURLConnection.getResponseCode();
            if (code == 200) {
                BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(httpURLConnection.getInputStream()));

                StringBuffer stringBuffer = new StringBuffer();
                String line;

                while ((line = bufferedReader.readLine()) != null) {
                    stringBuffer.append(line);
                }
                object =  new JSONObject(stringBuffer.toString());
             //   array = new JSONArray(stringBuffer.toString());
                array = object.getJSONArray("response");

            }

        } catch (Exception e) {

            e.printStackTrace();
        }
        return array;


    }

    @Override
    protected void onPreExecute() {
        super.onPreExecute();



    }

    @Override
    protected void onPostExecute(JSONArray array) {
        super.onPostExecute(array);
        try {
            for (int x = 0; x < array.length(); x++) {

                object = array.getJSONObject(x);
                ComonUserView commUserView=new ComonUserView();//  commonclass.setId(Integer.parseInt(jsonObject2.getString("pid").toString()));
                //pidArray.add(jsonObject2.getString("pid").toString());

                commUserView.setLid(object.get("lid").toString());
                commUserView.setUname(object.get("uname").toString());
                commUserView.setAboutme(object.get("aboutme").toString());
                commUserView.setHeight(object.get("height").toString());
                commUserView.setAge(object.get("age").toString());
                commUserView.setWeight(object.get("weight").toString());
                commUserView.setBodytype(object.get("bodytype").toString());
                commUserView.setRelationshipstatus(object.get("relationshipstatus").toString());
                commUserView.setImagepath(object.get("imagepath").toString());
                commUserView.setDistance(object.get("distance").toString());
                commUserView.setLookingfor(object.get("lookingfor").toString());
                commUserView.setStatus(object.get("status").toString());

                cm.add(commUserView);
            }
            custuserprof = new customadapterformainprofile(getActivity(),cm,Tab3.this);
          gridusername.setAdapter(custuserprof);
            //  listusername.setAdapter(custuserprof);
            } catch (Exception e) {

                e.printStackTrace();
        }
    }
Peggi answered 17/4, 2017 at 4:5 Comment(0)

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