How can I increment a char?

Question

I'm new to Python, coming from Java and C. How can I increment a char? In Java or C, chars and ints are practically interchangeable, and in certain loops, it's very useful to me to be able to do increment chars, and index arrays by chars.

How can I do this in Python? It's bad enough not having a traditional for(;;) looper - is there any way I can achieve what I want to achieve without having to rethink my entire strategy?

Algoid

Traditional for loop: for i in range(50): do_something_with(i). Come on, that's not so bad!! – Rossner

@SilentGhost: I'm splitting up an English dictionary for use in an Android app. Because the file individually is too big, I've written a Python script to split them up into words_aa.txt, words_ab.txt, etc... I needed to write a second script to generate a Java file with an array containing the Ids of the raw file resources of each word file (because I'm lazy), and I couldn't think of a better way to do it. – Algoid

you seem to be looking for something like [''.join(i) for i in itertools.product(string.ascii_lowercase, repeat=2)] – Neckcloth

@SilentGhost: Is that all it takes? If only it said in the manual. – Algoid

Answer 1

In Python 2.x, just use the ord and chr functions:

>>> ord('c')
99
>>> ord('c') + 1
100
>>> chr(ord('c') + 1)
'd'
>>> 

Python 3.x makes this more organized and interesting, due to its clear distinction between bytes and unicode. By default, a "string" is unicode, so the above works (ord receives Unicode chars and chr produces them).

But if you're interested in bytes (such as for processing some binary data stream), things are even simpler:

>>> bstr = bytes('abc', 'utf-8')
>>> bstr
b'abc'
>>> bstr[0]
97
>>> bytes([97, 98, 99])
b'abc'
>>> bytes([bstr[0] + 1, 98, 99])
b'bbc'

Darnelldarner

@Tom R. Don't! [miss the old days]. As you are trying a quickly achieve something or convert a piece of code, concepts and idioms of Python may seem to merely impede your progress and hardly be worth the learning curve... Be patient! You may even find that gaining proficiency in Python will improve your style in Java (and C, to a lesser extent). – Hobbes

worked like a charm. <br> The only change I'd do is for z, in which case I've assigned an 'a'. – Englishman

Answer 2

"bad enough not having a traditional for(;;) looper"?? What?

Are you trying to do

import string
for c in string.lowercase:
    ...do something with c...

Or perhaps you're using string.uppercase or string.letters?

Python doesn't have for(;;) because there are often better ways to do it. It also doesn't have character math because it's not necessary, either.

Coercive

Answer 3

Check this: USING FOR LOOP

for a in range(5):
    x='A'
    val=chr(ord(x) + a)
    print(val)

LOOP OUTPUT: A B C D E

Spadix

Answer 4

I came from PHP, where you can increment char (A to B, Z to AA, AA to AB etc.) using ++ operator. I made a simple function which does the same in Python. You can also change list of chars to whatever (lowercase, uppercase, etc.) is your need.

# Increment char (a -> b, az -> ba)
def inc_char(text, chlist = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'):
    # Unique and sort
    chlist = ''.join(sorted(set(str(chlist))))
    chlen = len(chlist)
    if not chlen:
        return ''
    text = str(text)
    # Replace all chars but chlist
    text = re.sub('[^' + chlist + ']', '', text)
    if not len(text):
        return chlist[0]
    # Increment
    inc = ''
    over = False
    for i in range(1, len(text)+1):
        lchar = text[-i]
        pos = chlist.find(lchar) + 1
        if pos < chlen:
            inc = chlist[pos] + inc
            over = False
            break
        else:
            inc = chlist[0] + inc
            over = True
    if over:
        inc += chlist[0]
    result = text[0:-len(inc)] + inc
    return result

Demarcusdemaria

Answer 5

There is a way to increase character using ascii_letters from string package which ascii_letters is a string that contains all English alphabet, uppercase and lowercase:

>>> from string import ascii_letters
>>> ascii_letters[ascii_letters.index('a') + 1]
'b'
>>> ascii_letters
'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'

Also it can be done manually;

>>> letters = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'
>>> letters[letters.index('c') + 1]
'd'

Conditioner

Answer 6

def doubleChar(str):
    result = ''
    for char in str:
        result += char * 2
    return result

print(doubleChar("amar"))

output:

aammaarr

Schaaff

Answer 7

For me i made the fallowing as a test.

string_1="abcd"

def test(string_1):
   i = 0
   p = ""
   x = len(string_1)
   while i < x:
    y = (string_1)[i]
    i=i+1
    s = chr(ord(y) + 1)
    p=p+s

   print(p)

test(string_1)

Measures

You have used same logic as accepted answer, what is the point of having new answer with similar solution? – Biff

i like clean code, in this section have not seen any solution that satisfies me, thus i put my 2 cents. – Measures