I have a string containing a ten-digit phone number and I want to format it with hyphens.
I am seeking a way to convert 123456790
to 123-456-7890
as phone numbers are typically formatted in the USA.
I have a string containing a ten-digit phone number and I want to format it with hyphens.
I am seeking a way to convert 123456790
to 123-456-7890
as phone numbers are typically formatted in the USA.
$areacode = substr($phone, 0, 3);
$prefix = substr($phone, 3, 3);
$number = substr($phone, 6, 4);
echo "$areacode-$prefix-$number";
You could also do it with regular expressions:
preg_match("/(\d{3})(\d{3})(\d{4})/",$phone,$matches);
echo "$matches[1]-$matches[2]-$matches[3]";
There are more ways, but either will work.
The following code will also validate your input.
preg_match('/^(\d{3})(\d{3})(\d{4})$/', $phone, $matches);
if ($matches) {
echo(implode('-', array_slice($matches, 1)));
}
else {
echo($phone); // you might want to handle wrong format another way
}
$p = $phone;
echo "$p[0]$p[1]$p[2]-$p[3]$p[4]-$p[5]$p[6]$p[7]$p[8]";
Fewest function calls. :)
echo substr($phone, 0, 3) . '-' . substr($phone, 3, 3) . '-' . substr($phone, 6);
More regexp :)
$phone = "1234567890";
echo preg_replace('/^(\d{3})(\d{3})(\d{4})$/', '\1-\2-\3', $phone);
If using a regular expression, I would not bother creating a temporary array to conver back into a string. Instead just tell preg_replace()
to make a maximum of two replacements after each sequence of three digits.
As a non-regex alternative, you could parse the string and reformat it using placeholders with sscanf()
and vprintf()
.
Codes: (Demo)
$string = '1234567890';
echo preg_replace('/\d{3}\K/', '-', $string, 2);
// 123-456-7890
Or
vprintf('%s-%s-%s', sscanf($string, '%3s%3s%4s'));
// 123-456-7890
Or
echo implode('-', sscanf($string, '%3s%3s%4s'));
// 123-456-7890
For such a simple task, involving a library is super-overkill, but for more complicated tasks there are libraries available:
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