How to get Bitmap from an Uri?

Question

How to get a Bitmap object from an Uri (if I succeed to store it in /data/data/MYFOLDER/myimage.png or file///data/data/MYFOLDER/myimage.png) to use it in my application?

Does anyone have an idea on how to accomplish this?

Consciousness

Answer 1

Here's the correct way of doing it:

protected void onActivityResult(int requestCode, int resultCode, Intent data)
{
    super.onActivityResult(requestCode, resultCode, data);
    if (resultCode == RESULT_OK)
    {
        Uri imageUri = data.getData();
        Bitmap bitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), imageUri);
    }
}

If you need to load very large images, the following code will load it in in tiles (avoiding large memory allocations):

BitmapRegionDecoder decoder = BitmapRegionDecoder.newInstance(myStream, false);  
Bitmap region = decoder.decodeRegion(new Rect(10, 10, 50, 50), null);

See the answer here

Ophthalmia

This code doesn't deal with bigger images though (basically anything wallpaper size). getBitmap() calls decodeStream() which fails with the OOM error from https://mcmap.net/q/18237/-handling-large-bitmaps. Any other advice? MediaStore.Images.Thumbnails.getThumbnail() apparently does not take a contentURI. – Younker

See the answer here: stackoverflow.com/questions/4753013/… – Ophthalmia

@MarkIngram Does this work with any local image or just the camera image? – Predecessor

@MarkIngram what if we dont have access to data.getData(), I mean if I simply open some image from gallery and I all know is about its path, how can I get uri and bitmap? – Neighbor

@Neighbor you should ask a new question instead of asking in the comments of an answer. By the way: have a look here developer.android.com/reference/android/net/Uri.html – Teletypewriter

It's telling me Unhandled exception: java.io.IOException with the red squiggly lines underneath. Any idea why? – Markland

Well I ended up putting a try-catch statement around it, and it got rid of the error. I wonder why it requires you to catch possible errors... – Markland

It throws IOException please update this answer with try catch block – Servant

@Mohsinkazi, try/catch isn't relevant to the answer, and it certainly doesn't improve the readability of the code. – Ophthalmia

@MarkIngram I agree that try catch block doesn't necessary but in some situation getBitmap() method throws exception. It happened with me so I suggested to add try catch block to make this code more usable. – Servant

@Mohsinkazi, the code isn't intended to be copy + pasted into a project without thought. It's merely providing an answer to the question. – Ophthalmia

@MarkIngram but not applicable for all those, who want Bitmap from an Uri. By the way thank you for your answer it help me. – Servant

bitmap object is becoming empty. what i am doing wrong? – Daigle

As this link states, you get an image thumbnail, which is about 400x100 on modern devices. – Savior

MediaStore.Images.Media.getBitmap(this.getContentResolver(), uri); is depricated now – Gunas

Answer 2

Here's the correct way of doing it, keeping tabs on memory usage as well:

protected void onActivityResult(int requestCode, int resultCode, Intent data)
{
  super.onActivityResult(requestCode, resultCode, data);
  if (resultCode == RESULT_OK)
  {
    Uri imageUri = data.getData();
    Bitmap bitmap = getThumbnail(imageUri);
  }
}

public static Bitmap getThumbnail(Uri uri) throws FileNotFoundException, IOException{
  InputStream input = this.getContentResolver().openInputStream(uri);

  BitmapFactory.Options onlyBoundsOptions = new BitmapFactory.Options();
  onlyBoundsOptions.inJustDecodeBounds = true;
  onlyBoundsOptions.inDither=true;//optional
  onlyBoundsOptions.inPreferredConfig=Bitmap.Config.ARGB_8888;//optional
  BitmapFactory.decodeStream(input, null, onlyBoundsOptions);
  input.close();

  if ((onlyBoundsOptions.outWidth == -1) || (onlyBoundsOptions.outHeight == -1)) {
    return null;
  }

  int originalSize = (onlyBoundsOptions.outHeight > onlyBoundsOptions.outWidth) ? onlyBoundsOptions.outHeight : onlyBoundsOptions.outWidth;

  double ratio = (originalSize > THUMBNAIL_SIZE) ? (originalSize / THUMBNAIL_SIZE) : 1.0;

  BitmapFactory.Options bitmapOptions = new BitmapFactory.Options();
  bitmapOptions.inSampleSize = getPowerOfTwoForSampleRatio(ratio);
  bitmapOptions.inDither = true; //optional
  bitmapOptions.inPreferredConfig=Bitmap.Config.ARGB_8888;//
  input = this.getContentResolver().openInputStream(uri);
  Bitmap bitmap = BitmapFactory.decodeStream(input, null, bitmapOptions);
  input.close();
  return bitmap;
}

private static int getPowerOfTwoForSampleRatio(double ratio){
  int k = Integer.highestOneBit((int)Math.floor(ratio));
  if(k==0) return 1;
  else return k;
}

The getBitmap() call from Mark Ingram's post also calls the decodeStream(), so you don't lose any functionality.

References:

• Android: Get thumbnail of image on SD card, given Uri of original image

• Handling large Bitmaps

Younker

This really helped me, although I think it's worth mentioning that the this keyword can't be used from within a static context. I passed it into the getThumbnail method as an argument and it works like a charm. – Amid

Can any one tell me what value should i give to THUMBNAILSIZE – Cormack

Closing and reopening the InputStream is actually necessary because the first BitmapFactory.decodeStream(...) call sets the reading position of the stream to the end, so the second call of the method wouldn't work anymore without reopening the stream! – Pot

THUMBNAILSIZE ,as the name suggests is the size of the image to be shown as a thumbnail ie. the thumbnail display size – Thrift

it gives me java.io.FileNotFoundException: No content provider: – Obsolete

@war_Hero THUMBNAILSIZE should be the size of the view which is going to show the thumbnail. – Teletypewriter

It's unnecessary to calculate the ratio as a power of two by yourself because the decoder itself rounds to sample size down to the nearest power of two. Therefore the method call getPowerOfTwoForSampleRatio() can be skipped. See: developer.android.com/reference/android/graphics/… – Teletypewriter

Answer 3

It seems that MediaStore.Images.Media.getBitmap was deprecated in API 29. The recommended way is to use ImageDecoder.createSource which was added in API 28.

Here's how getting the bitmap would be done:

val bitmap = if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.P) {
    ImageDecoder.decodeBitmap(ImageDecoder.createSource(requireContext().contentResolver, imageUri))
} else {
    MediaStore.Images.Media.getBitmap(requireContext().contentResolver, imageUri)
}

IMPORTANT: ImageDecoder.decodeBitmap read EXIF orientation, Media.getBitmap doesn't

Hamamatsu

The documentation clearly says "This method should be done in a worker thread, not the main thread!" – Skew

This doesn't work on newer versions of android. – Pauper

Answer 4

try
{
    Bitmap bitmap = MediaStore.Images.Media.getBitmap(c.getContentResolver() , Uri.parse(paths));
}
catch (Exception e) 
{
    //handle exception
}

and yes path must be in a format of like this

file:///mnt/sdcard/filename.jpg

Absence

@Dhananjay Thank you, your hint saves my day, and it works to load the thumbnail bitmap from Content Provider. – Rosalia

In addition, the Uri.parse() must contain URI format, just like: Uri.parse("file:///mnt/sdcard/filename.jpg"), if not we will get java.io.FileNotFoundException: No content provider. – Rosalia

Some editorialization would be nice, but this is a good concise answer to the OPs question that works in most cases. This is a nice answer to have on the page for the sake of distilling out the piece of these other answers that directly answer the OPs questions. – Maliamalice

@AndroidNewBee c is Context object. – Absence

not working in my case getting exception Caused by: java.lang.NullPointerException: Attempt to invoke virtual method 'java.lang.String android.net.Uri.getScheme()' on a null object reference – Resurrection

Answer 5

private void uriToBitmap(Uri selectedFileUri) {
    try {
        ParcelFileDescriptor parcelFileDescriptor =
                getContentResolver().openFileDescriptor(selectedFileUri, "r");
        FileDescriptor fileDescriptor = parcelFileDescriptor.getFileDescriptor();
        Bitmap image = BitmapFactory.decodeFileDescriptor(fileDescriptor);

        parcelFileDescriptor.close();
    } catch (IOException e) {
        e.printStackTrace();
    }
}

Cloak

it's works on all sdk.. Thanks. it's alternative way of Bitmap bitmap = MediaStore.Images.Media.getBitmap(context.getContentResolver(), uri); – Sedgewinn

MediaStore.Images.Media.getBitmap(context.getContentResolver(), uri) is deprecated – Liger

Answer 6

This is the easiest solution:

Bitmap bitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), uri);

Nucleon

Awesome it's working fine – Pinworm

Answer 7

You can retrieve bitmap from uri like this

Bitmap bitmap = null;
try {
    bitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), imageUri);
} catch (IOException e) {
    e.printStackTrace();
}

Urana

Answer 8

Uri imgUri = data.getData();
Bitmap bitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), imgUri);

Migratory

Could you please elaborate on how this code works and how it answers the question? – Pup

Answer 9

Bitmap bitmap = null;
ContentResolver contentResolver = getContentResolver(); 
try {
    if(Build.VERSION.SDK_INT < 28) {
        bitmap = MediaStore.Images.Media.getBitmap(contentResolver, imageUri);
    } else {
        ImageDecoder.Source source = ImageDecoder.createSource(contentResolver, imageUri);
        bitmap = ImageDecoder.decodeBitmap(source);
    }
} catch (Exception e) {
    e.printStackTrace();
}

Eureetloir

Answer 10

private fun setImage(view: ImageView, uri: Uri) {
        val stream = contentResolver.openInputStream(uri)
        val bitmap = BitmapFactory.decodeStream(stream)
        view.setImageBitmap(bitmap)
}

Histoplasmosis

Answer 11

by using glide library you can get bitmap from uri,

almost in samsung devices image rotated when and we have to check rotation using exifinterface

but using glide no need to check rotation, image always correctly received.

in kotlin you can get bitmap as

CoroutineScope(Dispatchers.IO).launch {
   var bitmap = Glide.with(context).asBitmap().load(imageUri).submit().get()//this is synchronous approach                  
}

I am using this dependency

api 'com.github.bumptech.glide:glide:4.12.0'
kapt 'com.github.bumptech.glide:compiler:4.12.0'

Silica

Answer 12

Inset of getBitmap which is depricated now I use the following approach in Kotlin

PICK_IMAGE_REQUEST ->
    data?.data?.let {
        val bitmap = BitmapFactory.decodeStream(contentResolver.openInputStream(it))
        imageView.setImageBitmap(bitmap)
    }

Pula

Answer 13

  InputStream imageStream = null;
    try {
        imageStream = getContext().getContentResolver().openInputStream(uri);
    } catch (FileNotFoundException e) {
        e.printStackTrace();
    }
    final Bitmap selectedImage = BitmapFactory.decodeStream(imageStream);

Heptachord

Answer 14

ContentResolver cr = context.getContentResolver();
try (InputStream input = cr.openInputStream(url)) {
    Bitmap bitmap = BitmapFactory.decodeStream(input);
}

Janik

Consider explaining your answer a little bit. Especially the cr (contentResolver) part. – Burleigh

Answer 15

Use startActivityForResult metod like below

        startActivityForResult(new Intent(Intent.ACTION_PICK).setType("image/*"), PICK_IMAGE);

And you can get result like this:

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    if (resultCode != RESULT_OK) {
        return;
    }
    switch (requestCode) {
        case PICK_IMAGE:
            Uri imageUri = data.getData();
            try {
                Bitmap bitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), imageUri);
            } catch (IOException e) {
                e.printStackTrace();
            }
         break;
    }
}

Heighho

Answer 16

I have try a lot of ways. this work for me perfectly.

If you choose pictrue from Gallery. You need to be ware of getting Uri from intent.clipdata or intent.data, because one of them may be null in different version.

  private fun onChoosePicture(data: Intent?):Bitmap {
        data?.let {
            var fileUri:Uri? = null

              data.clipData?.let {clip->
                  if(clip.itemCount>0){
                      fileUri = clip.getItemAt(0).uri
                  }
              }
            it.data?.let {uri->
                fileUri = uri
            }


               return MediaStore.Images.Media.getBitmap(this.contentResolver, fileUri )
}

Conclude

Answer 17

I don't see the right answer, so I'll put this extension here

fun Context.getBitmap(uri: Uri): Bitmap =
    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.P) ImageDecoder.decodeBitmap(ImageDecoder.createSource(this.contentResolver, uri))
    else MediaStore.Images.Media.getBitmap(this.contentResolver, uri)

Example in code:

val bitmap = context.getBitmap(uri)

Tip: You can also update the extension for activity/fragment, so you don't need to write the context at all. A little more synth sugar)

Fingered

Answer 18

val bitmap = context.contentResolver.openInputStream(uri).use { data ->
        BitmapFactory.decodeStream(data)
    }

You need to open inputstream with

use

as it will automatically close the stream after operation complete.

Atilt

Answer 19

you can do this structure:

protected void onActivityResult(int requestCode, int resultCode, Intent imageReturnedIntent) {
    super.onActivityResult(requestCode, resultCode, imageReturnedIntent);
    switch(requestCode) {
        case 0:
            if(resultCode == RESULT_OK){
                    Uri selectedImage = imageReturnedIntent.getData();
                    Bundle extras = imageReturnedIntent.getExtras();
                    bitmap = extras.getParcelable("data");
            }
            break;
   }

by this you can easily convert a uri to bitmap. hope help u.

Aquila

This is not working in android nougat 7.1.1 version. This extras.getParcelable("data"); is returning null – Edouard

Answer 20

(KOTLIN) So, as of April 7th, 2020 none of the above mentioned options worked, but here's what worked for me:

1. If you want to store the bitmap in a val and set an imageView with it, use this:

   val bitmap = BitmapFactory.decodeFile(currentPhotoPath).also { bitmap -> imageView.setImageBitmap(bitmap) }

2. If you just want to set the bitmap to and imageView, use this:

   BitmapFactory.decodeFile(currentPhotoPath).also { bitmap -> imageView.setImageBitmap(bitmap) }

Abreu

Answer 21

* For getting bitmap from uri. Work for me perfectly.
    
    
    public static Bitmap decodeUriToBitmap(Context mContext, Uri sendUri) {
          Bitmap getBitmap = null;
          try {
            InputStream image_stream;
            try {
              image_stream = mContext.getContentResolver().openInputStream(sendUri);
              getBitmap = BitmapFactory.decodeStream(image_stream);
            } catch (FileNotFoundException e) {
              e.printStackTrace();
            }
          } catch (Exception e) {
            e.printStackTrace();
          }
          return getBitmap;
        }

Powys

Answer 22

Full method to get image uri from mobile gallery.

protected void onActivityResult(int requestCode, int resultCode, Intent data) {
        super.onActivityResult(requestCode, resultCode, data);

  if (requestCode == PICK_IMAGE_REQUEST && resultCode == RESULT_OK && data != null && data.getData() != null) {
                Uri filePath = data.getData();

     try { //Getting the Bitmap from Gallery
           Bitmap bitmap = MediaStore.Images.Media.getBitmap(getContentResolver(), filePath);
           rbitmap = getResizedBitmap(bitmap, 250);//Setting the Bitmap to ImageView
           serImage = getStringImage(rbitmap);
           imageViewUserImage.setImageBitmap(rbitmap);
      } catch (IOException e) {
           e.printStackTrace();
      }


   }
}

Adust

Answer 23

A recurring problem that I faced using the solutions provided here is:

Failed to find provider info for com.samsung.systemui.navillera.navilleraprovider

This will prevent your bitmap from being loaded.

I tried this instead and it works! Praise God.

The explanation is that the uri provided needs to be converted into a file path.

Bitmap b1 = MediaStore.Images.Media.getBitmap(this.getContentResolver(), Uri.fromFile(new File(uri1.toString())));

Jarmon

Answer 24

Use coil libray for this purpose on 2022.

https://coil-kt.github.io/coil/compose/

for jetpack compose

            AsyncImage(
                model = uriOfImage,
                contentDescription = null,
            )

Quincunx

this irreverent as he needed a bitmap not an image UI – Halbeib