Unfortunately, when the slave broker starts so does the CamelContext along with the routes. However you can accomplish this by doing the following:
On the camelContext deployed with slave broker add the following autoStartup attribute to prevent the routes from starting:
<camelContext id="camel" xmlns="http://camel.apache.org/schema/spring" autoStartup="false">
...
</camelContext>
Next you need to create a class that implements the ActiveMQ Service Interface. A sample of this would be as follows:
package com.fusesource.example;
import org.apache.activemq.Service;
import org.apache.camel.spring.SpringCamelContext;
import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
/**
* Example used to start and stop the camel context using the ActiveMQ Service interface
*
*/
public class CamelContextService implements Service
{
private final Logger LOG = LoggerFactory.getLogger(CamelContextService.class);
SpringCamelContext camel;
@Override
public void start() throws Exception {
try {
camel.start();
} catch (Exception e) {
LOG.error("Unable to start camel context: " + camel);
e.printStackTrace();
}
}
@Override
public void stop() throws Exception {
try {
camel.stop();
} catch (Exception e) {
LOG.error("Unable to stop camel context: " + camel);
e.printStackTrace();
}
}
public SpringCamelContext getCamel() {
return camel;
}
public void setCamel(SpringCamelContext camel) {
this.camel = camel;
}
}
Then in broker's configuration file, activemq.xml, add the following to register the service:
<services>
<bean xmlns="http://www.springframework.org/schema/beans" class="com.fusesource.example.CamelContextService">
<property name="camel" ref="camel"/>
</bean>
</services>
Now, once the slave broker takes over as the master, the start method will be invoked on the service class and the routes will be started.
I have also posted a blog about this here: http://jason-sherman.blogspot.com/2012/04/activemq-how-to-startstop-camel-routes.html