I have a class Receiver with an ActionBlock:
public class Receiver<T> : IReceiver<T>
{
private ActionBlock<T> _receiver;
public Task<bool> Send(T item)
{
if(_receiver!=null)
return _receiver.SendAsync(item);
//Do some other stuff her
}
public void Register (Func<T, Task> receiver)
{
_receiver = new ActionBlock<T> (receiver);
}
//...
}
The Register-Action for the ActionBlock is a async-Method with a await-Statement:
private static async Task Writer(int num)
{
Console.WriteLine("start " + num);
await Task.Delay(500);
Console.WriteLine("end " + num);
}
Now what i want to do is to wait synchronously (if a condition is set) until the action method is finished to get an exclusive behavior:
var receiver = new Receiver<int>();
receiver.Register((Func<int, Task) Writer);
receiver.Send(5).Wait(); //does not wait the action-await here!
The Problem is when the "await Task.Delay(500);" statement is executed, the "receiver.Post(5).Wait();" does not wait anymore.
I have tried several variants (TaskCompletionSource, ContinueWith, ...) but it does not work.
Has anyone an idea how to solve the problem?
_receiver
into aTransformBlock
and put the following action into a newActionBlock
, linked to_receiver
? – Dor