In the error page I would like to display the URL what the user requested.
In my web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
id="WebApp_ID"
version="3.0">
<display-name>MyStuff</display-name>
<error-page>
<error-code>404</error-code>
<location>/WEB-INF/error-404.jsp</location>
</error-page>
</web-app>
This will forward to error-404.jsp, and here is the content of that file:
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Page Not found</title>
</head>
<body>
<p align="center">
<%
out.println("Requested resource: " + request.getRequestURL()+ " not found");
%>
</body>
</html>
The problem it is the request.getRequestURL()
need to be changed, but don't know the keyword for what to search.
When I start the browser for http://localhost:8080/MyStuff
then I get the following error:
Requested resource: http://localhost:8080/MyStuff/WEB-INF/error-404.jsp not found
How to solve this?
(String) req.getAttribute("javax.servlet.error.request_uri");
– Undertrick