Calling an IO Monad inside an Arrow

The type IO a -> Arrow a doesn't make sense; Arrow is a type class, not a specific type, much like Monad or Num. Specifically, an instance of Arrow is a type constructor taking two parameters that describes things that can be composed like functions, matching types end-to-end. So, converting IO a to an arrow could perhaps be called a conceptual type error.

I'm not sure exactly what you're trying to do, but if you really want to be using IO operations as part of an Arrow, you need your Arrow instance to include that. The simplest form of that is to observe that functions with types like a -> m b for any Monad instance can be composed in the obvious way. The hxt package seems to provide a more complicated type:

newtype IOSLA s a b = IOSLA { runIOSLA :: s -> a -> IO (s, [b]) }

This is some mixture of the IO, State, and [] monads, attached to a function as above such that you can compose them going through all three Monads at each step. I haven't really used hxt much, but if these are the Arrows you're working with, it's pretty simple to lift an arbitrary IO function to serve as one--just pass the state value s through unchanged, and turn the output of the function into a singleton list. There may already be a function to do this for you, but I didn't see one at a brief glance.

Basically, you'd want something like this:

liftArrIO :: (a -> IO b) -> IOSLA s a b
liftArrIO f = IOSLA $ \s x -> fmap (\y -> (s, [y])) (f x)

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