How can I access a single XML element's value using C#.net web-pages with WebMatrix?
Asked Answered
P

1

6

I've looked at a lot of resources, done a lot of research, and tried many "best-guesses" to access a single element at a time using WebMatrix with C#, web-pages, however nothing I am trying is getting through.

Consider a simple xml document that looks like this:

<root>
    <requisitionData>
        <element1>I am element 1</element1>
        <element2>I am element 2</element2>
    </requisitionData>
</root>

I know I can use a foreach loop, like so:

@using System.Xml.Linq

XDocument doc = XDocument.Load(Server.MapPath("~/User_Saves/cradebaugh/testFile.xml"));

foreach (XElement element in doc.Descendants("requisitionData"))
{
    @element.Value
}

And that, of course, works fine. But what if I simply wanted to store the single element, <element1>'s value in a string variable?

I've looked here (link below), but I can't make heads or tails of this code (it barely even looks like C# to me, but then again, I'm so new to parsing XML...):

http://social.msdn.microsoft.com/Forums/en-US/csharpgeneral/thread/b14ce4d1-77f1-420d-ad91-0989794a1d45/

I've also checked here: How to Get XML Node from XDocument

But the code shown makes no sense to me here either. I keep thinking there must be a simpler way to do this, hopefully without learning a whole new querying approach.

---------------------------------THINGS I'VE TRIED---------------------------------

XDocument doc = XDocument.Load(Server.MapPath("~/User_Saves/cradebaugh/testFile.xml"));

string element = doc.Descendants("requisitionData").Descendants("element1").Value;

Error I receive: "missing using directive or assembly reference

XDocument doc = XDocument.Load(Server.MapPath("~/User_Saves/cradebaugh/testFile.xml"));

XElement element = doc.Descendants("element1");
string val = element.Value;

Error I receive: Cannot implicitly convert type 'System.Collections.Generic.IEnumerable' to 'System.Xml.Linq.XElement'. An explicit conversion exists (are you missing a cast?)

I have, indeed, tried other things, but I get pretty much the same errors as shown above. Am I making this harder than it is, or am I oversimplifying it?

-------------------------UPDATE------------------------------

I was able to get this to work:

string element = doc.Element("root").Element("requisitionData").Element("element1").Value;

@element

However, one thing that concerns me about this approach is that .Element selects the 'first' match, so in an xml document that looks like this:

<root>
    <requisitionData>
        <element1>I am element 1</element1>
        <element2>I am element 2</element2>
    </requisitionData>
    <requisitionData>
        <element1>I am element 1</element1>
        <element2>I am element 2</element2>
    </requisitionData>
</root>

How could I access the second occurrence of <element1>?

Pig answered 9/4, 2013 at 13:46 Comment(1)
After having this issue resolved for a couple of days (thanks to the answer below), I'm gonna have to say that using XPathSelectElement(s) seems to be the way to go. XPath is powerful (way more than I realized) accurate, and completely flexible, whether I want a single element or many.Pig
T
5
@using System.Xml.Linq

XDocument doc = XDocument.Load(Server.MapPath("~/User_Saves/cradebaugh/testFile.xml"));

foreach (XElement element in doc.Element("root").Element("requisitionData").Descendants())
{
    string value = element.Value;
}

or with XPath:

@using System.Xml.Linq
@using System.Xml.XPath

XDocument doc = XDocument.Load(Server.MapPath("~/User_Saves/cradebaugh/testFile.xml"));

foreach (XElement element in doc.XPathSelectElement("//requisitionData").Descendants())
{
    string value = element.Value;
}

UPDATE:

And if you wanted to select for example the second <element1> node from your updated example:

string value = doc.XPathSelectElement("//requisitionData[2]/element1").Value;
Theurer answered 9/4, 2013 at 13:57 Comment(8)
Thanks for the answer but I am explicitly wanting only a single element, thus alleviating the need for a code 'loop'Pig
Also, I don't see how this selects a single element. There is more than one result that will be iterated through, given the foreach loop conditions.Pig
Which particular node in the XML do you want? You could use the XPath example I have shown in my answer to get any specific node you like. For example if you wanted to get the value of the first <element1> node you would have written string value = doc.XPathSelectElements("//requisitionData/element1").First().Value;.Theurer
I certainly have no problem studying XPath, but let me express my thoughts this way: If I wanted to do this "client-side" (which I really don't) I could simply use a jQuery(CSS) selector to grab any single element by id, or grab multiples by class (or tag name for that matter) and iterate through them using .length. I feel like I have full control over exactly which elements I want to select and gather the data from. I would love to achieve this level of control "server-side" if possible (I'm sure it is, at least with XPath, although it may not be as simple).Pig
Until your examples, though, I had no idea how to use XPath with C#.net, so, again, thank you for that!Pig
I really don't understand what you are trying to achieve and what problems are you encountering. The doc.XPathSelectElements("//requisitionData/element1") expression will give you a list of all <element1> nodes. Isn't what you were asking for? Also I don't see what client side CSS has to do with the question here. All the examples are using server side code.Theurer
I'm sorry if I have confused you, but the question is pretty clear, what I am really asking is how to select a "single" element (not a list, not a collection, not all <element1>s but a single individual <element1> You're right "client-side" has nothing to do with this, except that I was simply using it as an example to explain the level of control I would like to achieve "server-side". Is there a way to use XPath (or any other C#.net method) to select a single element by 'id' or 'class', by any chance? Again, sorry for the confusion, but the original question states "single element"Pig
Like this: doc.XPathSelectElement("//requisitionData/element1"). And if you wanted the second element1 then simply adapt your XPath expression: doc.XPathSelectElement("//requisitionData[2]/element1"). I have updated my answer to provide you with a specific example.Theurer

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