Dealing with speech marks with string.match

Question

I have an xml page that I have a monitoring system scanning, here is the source data:

`<queues>
<queue name="workQueue">
<stats size="0" consumerCount="28" enqueueCount="29320" dequeueCount="37000"/>

And here is the code I have so far:

local pattern = " size=(%d+) "

local a = alarm.get("CO13974960-19518")

local vsize = string.match(a.message, pattern)

local sum = vsize

I'm trying to target this bit of data from the XML page:

stats size="0"

The value "0" is the number I am interested in, and I'm looking for a way to capture that figure (no matter what it reaches) via the script.

I think my script is looking for:

size=0 rather than size="0"

But I'm unsure on the correct syntax on how to do this.

Fpc

Use escaped quotes inside string literals: local pattern = " size=\"(%d+)\" " – Beggarweed

Thank you, this works perfectly! – Fpc

Answer 1

In general, it's not a good idea to use Lua pattern (or regex) to parse XML, use a XML parser instead.

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Anyway, in this example,

local pattern = " size=(%d+) "

• Whitespace matters, so the white space in the beginning and end are trying to match white space character but failed.
• You have already noticed that you need double quotes around (%d), they have to be escaped in double quoted strings.
• + is greedy, it might work here, but the non-greedy - is a better choice.

This works

local pattern = "size=\"(%d-)\""

Note you could use single quotes strings so that you don't need escape double quotes:

local pattern = 'size="(%d-)"'

Archimandrite