How to pass a single object[] to a params object[]
Asked Answered
S

7

128

I have a method which takes params object[] such as:

void Foo(params object[] items)
{
    Console.WriteLine(items[0]);
}

When I pass two object arrays to this method, it works fine:

Foo(new object[]{ (object)"1", (object)"2" }, new object[]{ (object)"3", (object)"4" } );
// Output: System.Object[]

But when I pass a single object[], it does not take my object[] as the first param, instead it takes its all elements like I wanted to pass them one by one:

Foo(new object[]{ (object)"1", (object)"2" });
// Output: 1, expected: System.Object[]

How do I pass a single object[] as a first argument to a params array?

Serif answered 30/8, 2008 at 21:22 Comment(0)
M
103

A simple typecast will ensure the compiler knows what you mean in this case.

Foo((object)new object[]{ (object)"1", (object)"2" }));

As an array is a subtype of object, this all works out. Bit of an odd solution though, I'll agree.

Markman answered 30/8, 2008 at 21:36 Comment(2)
the way params works seems unnecessary, and suboptimal c# design, given what we’ve become used to in other languages. params could have been made to only accept one form, and a spread like feature could be added that would benefit the entire language, not just this case. for example, we could force all param calls to be Foo(obj[0], obj[1]), and then have a separate spread operator allowing Foo(...obj).Skepticism
realized i hadn’t made clear I have great respect for anders hejlsberg, he’s one of the best language designers in the world. but we can think about improvements to anyone’s work given enough hindsight, hence technology.Skepticism
H
78

The params parameter modifier gives callers a shortcut syntax for passing multiple arguments to a method. There are two ways to call a method with a params parameter:

1) Calling with an array of the parameter type, in which case the params keyword has no effect and the array is passed directly to the method:

object[] array = new[] { "1", "2" };

// Foo receives the 'array' argument directly.
Foo( array );

2) Or, calling with an extended list of arguments, in which case the compiler will automatically wrap the list of arguments in a temporary array and pass that to the method:

// Foo receives a temporary array containing the list of arguments.
Foo( "1", "2" );

// This is equivalent to:
object[] temp = new[] { "1", "2" );
Foo( temp );

In order to pass in an object array to a method with a "params object[]" parameter, you can either:

1) Create a wrapper array manually and pass that directly to the method, as mentioned by lassevk:

Foo( new object[] { array } );  // Equivalent to calling convention 1.

2) Or, cast the argument to object, as mentioned by Adam, in which case the compiler will create the wrapper array for you:

Foo( (object)array );  // Equivalent to calling convention 2.

However, if the goal of the method is to process multiple object arrays, it may be easier to declare it with an explicit "params object[][]" parameter. This would allow you to pass multiple arrays as arguments:

void Foo( params object[][] arrays ) {
  foreach( object[] array in arrays ) {
    // process array
  }
}

...
Foo( new[] { "1", "2" }, new[] { "3", "4" } );

// Equivalent to:
object[][] arrays = new[] {
  new[] { "1", "2" },
  new[] { "3", "4" }
};
Foo( arrays );

Edit: Raymond Chen describes this behavior and how it relates to the C# specification in a new post.

Hiphuggers answered 1/9, 2008 at 16:28 Comment(0)
A
9

This is a one line solution involving LINQ.

var elements = new String[] { "1", "2", "3" };
Foo(elements.Cast<object>().ToArray())
Antitoxin answered 18/2, 2016 at 6:54 Comment(0)
R
3

You need to encapsulate it into another object[] array, like this:

Foo(new Object[] { new object[]{ (object)"1", (object)"2" }});
Ritchie answered 30/8, 2008 at 21:31 Comment(0)
T
2

Another way to solve this problem (it's not so good practice but looks beauty):

static class Helper
{
    public static object AsSingleParam(this object[] arg)
    {
       return (object)arg;
    }
}

Usage:

f(new object[] { 1, 2, 3 }.AsSingleParam());
Tidemark answered 11/4, 2018 at 15:23 Comment(0)
A
1

One option is you can wrap it into another array:

Foo(new object[]{ new object[]{ (object)"1", (object)"2" } });

Kind of ugly, but since each item is an array, you can't just cast it to make the problem go away... such as if it were Foo(params object items), then you could just do:

Foo((object) new object[]{ (object)"1", (object)"2" });

Alternatively, you could try defining another overloaded instance of Foo which takes just a single array:

void Foo(object[] item)
{
    // Somehow don't duplicate Foo(object[]) and
    // Foo(params object[]) without making an infinite
    // recursive call... maybe something like
    // FooImpl(params object[] items) and then this
    // could invoke it via:
    // FooImpl(new object[] { item });
}
Articulator answered 30/8, 2008 at 21:31 Comment(0)
I
1
new[] { (object) 0, (object) null, (object) false }
Imperium answered 21/6, 2012 at 23:37 Comment(0)

© 2022 - 2024 — McMap. All rights reserved.