Swift: how to use PREPROCESSOR Flags (like `#if DEBUG`) to implement API keys?
Asked Answered
P

4

129

In Objective-C it was sometimes useful to use static string constants to define alternate API keys (for example to differentiate between RELEASE and DEBUG keys for analytics packages, like MixPanel, Flurry or Crashlytics):

#if DEBUG
static NSString *const API_KEY = @"KEY_A";
#else
static NSString *const API_KEY = @"KEY_B";
#endif

and then...

[Analytics startSession:API_KEY];

How does this translate to Swift, since the Swift compiler no longer uses a preprocessor?

Procrastinate answered 7/8, 2016 at 11:58 Comment(0)
S
209

Apple included full support for Swift preprocessor flags as of Xcode 8, so it's no longer necessary to set these values in "Other Swift Flags".

The new setting is called "Active Compilation Conditions", which provides top-level support for the Swift equivalent of preprocessor flags. You use it in exactly the same way as you would "Other Swift Flags", except there's no need to prepend the value with a "-D" (so it's just a little cleaner).

From the Xcode 8 release notes:

Active Compilation Conditions is a new build setting for passing conditional compilation flags to the Swift compiler. Each element of the value of this setting passes to swiftc prefixed with -D, in the same way that elements of Preprocessor Macros pass to clang with the same prefix. (22457329)

enter image description here

You use the above setting like so:

#if DEBUG
    let accessToken = "DebugAccessToken"
#else
    let accessToken = "ProductionAccessToken"
#endif
Strage answered 20/11, 2017 at 15:28 Comment(6)
Note: you should not specify =1 or any other = value. Rather, you need to just specify the flag name. :]Gush
@Gush I don't disagree, but I'm not sure how your comment applies here.Strage
This is a helpful answer, but coming from an Objective-C background (as I imagine many iOS developers are), I assumed that I needed to specify =1... I lost a bit of time trying to figure out why it wasn't working when I did. So, I thought I'd share this tidbit to help the next fellow. :] Anyways, thanks for your answer here!Gush
@JRG-Developer, @Dan Loewenherz I have set both DEBUG in Active Compilation Conditions and DEBUG=1 in Preprocessor Macros and this configuration does not work at all. Should i remove DEBUG=1 ?? Not clear from the above comments.Clever
@Clever The only things I can think of are 1) you're building under another release configuration or 2) the compilation conditions are being overriden later on in the resolution chain.Strage
@DanLoewenherz You are absolutely right. I had set "DEBUG" for archive configuration in my target settings, so every time it runs a Debug statement and never runs the release condition. Anyone who is facing issue then please check you target's Build Configuration first. Check this answer #9063600 for more info.Clever
P
135

UPDATED: Xcode 8 now supports this automatically, see @dwlz's response above.

Prior to Xcode 8, you could still use Macros in the same way:

#if DEBUG
let apiKey = "KEY_A"
#else
let apiKey = "KEY_B"
#endif

However in order for them to be picked up by Swift, you need to set "Other Swift Flags" in your target's Build Settings:

  • Open Build Settings for your target
  • Search for "other swift flags"
  • Add the macros you wish to use, preceded by the -D flag

enter image description here

Procrastinate answered 7/8, 2016 at 11:58 Comment(1)
you made my day! for me It didn't work without -D prefixPollinate
M
11

In swift packages you have to do this inside of the swiftSettings argument to .target in your Package.swift file. Use the define method (Apple documentation) or Swift documentation

targets: [
.target(name: String,
            dependencies: [Target.Dependency],
            path: String?,
            exclude: [String]?,
            sources: [String]?,,
            cSettings: [CSetting]?,
            cxxSettings: [CXXSetting]?,
            swiftSettings: [SwiftSetting]?,
            linkerSettings: [LinkerSetting]?),

Mine looks like this and it works!

            swiftSettings: [
               .define("VAPOR")
            ]

in my code I can conditionally compile using this:

#if VAPOR
Mufi answered 29/7, 2020 at 16:18 Comment(3)
is this still working for you?Earhart
@Earhart yes. I'm using swift-tools-version:5.7 and I compile my project both in linux and Mac via Xcode 14.3Mufi
thanks. I realised I needed to add swiftSettings for each of my targets.Earhart
I
8

As a follow up observation, try not to keep api keys / secrets in plaintext in the repository. Use a secrets management system to load the keys / secrets into the user's environment variables. Otherwise step 1 is necessary, if acceptable.

  1. Put the "secrets" in a plaintext file above in the enclosing repository
  2. Create a ../set_keys.sh that contains a list of export API_KEY_A='<plaintext_key_aef94c5l6>' (use single quote to prevent evaluation)
  3. Add a Run script phase that can source ../set_keys.sh and move it to the top of execution order
  4. In Build Settings > Preprocessor Macros, add to defines as necessary such as API_KEY_A="$API_KEY_A"

That captures the environment variable into the compiler define which is later used in each clang invocation for each source file.

Example directory structure

[10:33:15] ~/code/memo yes? tree -L 2 .
.
├── Memo
│   ├── Memo
│   ├── Memo.xcodeproj
│   ├── Memo.xcworkspace
│   ├── Podfile
│   ├── Podfile.lock
│   └── Pods
└── keys
Illboding answered 1/8, 2019 at 5:34 Comment(0)

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