I'm trying to unzip a zip file directly from the php://input
stream. I'm running Laravel Homestead, PHP 7.1.3-3+deb.sury.org~xenial+1
, with an endpoint at myproject.app/upload
, here is the curl
command:
curl --request POST \
--url 'http://myproject.app/upload' \
--data-binary "@myfile.zip" \
Here is a list of all the methods I've tried, which all fail:
dd(file_get_contents('compress.zlib://php://input'));
file_get_contents(): cannot represent a stream of type Input as a File Descriptor
$fh = fopen('php://input', 'rb');
stream_filter_append($fh, 'zlib.inflate', STREAM_FILTER_READ, array('window'=>15));
$data = '';
while (!feof($fh)) {
$data .= fread($fh, 8192);
}
dd($data);
""
$zip = new ZipArchive;
$zip->open('php://input');
$zip->extractTo(storage_path() . '/' . 'myfile');
$zip->close();
ZipArchive::extractTo(): Invalid or uninitialized Zip object
Here are all the links I've found on the subject:
http://php.net/manual/en/wrappers.php#83220
http://php.net/manual/en/wrappers.php#109657
http://php.net/manual/en/wrappers.compression.php#118461
https://secure.phabricator.com/rP42566379dc3c4fd01a73067215da4a7ca18f9c17
https://arjunphp.com/how-to-unpack-a-zip-file-using-php/
I'm beginning to think that it's not possible to operate on streams with PHP's built-in zip functionality. The overhead and complexity of writing temporary files would be pretty disappointing. Does anyone know how to do this, or is it a bug?