Using collections.Counter to count emojis with different colors

Question

I would like to use the collections.Counter class to count emojis in a string. It generally works fine, however, when I introduce colored emojis the color component of the emoji is separated from the emoji like so:

>>> import collections
>>> emoji_string = "👌🏻👌🏼👌🏽👌🏾👌🏿"
>>> emoji_counter = collections.Counter(emoji_string)
>>> emoji_counter.most_common()
[('👌', 5), ('🏻', 1), ('🏼', 1), ('🏽', 1), ('🏾', 1), ('🏿', 1)]

How can I make the most_common() function return something like this instead:

[('👌🏻', 1), ('👌🏼', 1), ('👌🏽', 1), ('👌🏾', 1), ('👌🏿', 1)]

I'm using Python 3.6

Exeunt

Answer 1

You'll have to split your string into separate clusters. Each of your emoji is really two codepoints; the emoji and a EMOJI MODIFIER FITZPATRICK TYPE X codepoint:

>>> print(emoji_string[0])
👌
>>> print(emoji_string[1])
🏻
>>> print(emoji_string[:2])
👌🏻
>>> print(ascii(emoji_string[:2]))
'\U0001f44c\U0001f3fb'
>>> import unicodedata
>>> unicodedata.name(emoji_string[1])
'EMOJI MODIFIER FITZPATRICK TYPE-1-2'

You could use a regular expression to keep those with the preceding emoji:

import re

char_with_modifier = re.compile(r'(.[\U0001f3fb-\U0001f3ff]?)')
split_emoji = char_with_modifier.findall(emoji_string)

and count the result.

Demo:

>>> import re
>>> from collections import Counter
>>> emoji_string = "👌🏻👌🏼👌🏽👌🏾👌🏿"
>>> char_with_modifier = re.compile(r'(.[\U0001f3fb-\U0001f3ff]?)')
>>> Counter(char_with_modifier.findall(emoji_string))
Counter({'👌🏻': 1, '👌🏼': 1, '👌🏽': 1, '👌🏾': 1, '👌🏿': 1})

Frail

Thanks, this helped a lot. I tweaked the regex a bit because I'd like it to find regular emojis as well and not just the colored ones (.(?:[\U0001f3fb-\U0001f3ff])?) – Advice

Answer 2

import regex
from collections import Counter
emoji_string = "👌🏻👌🏼👌🏽👌🏾👌🏿"
data = regex.findall(r'\X',emoji_string)
print(Counter(data))

Expected output

Counter({'👌🏻': 1, '👌🏼': 1, '👌🏽': 1, '👌🏾': 1, '👌🏿': 1})

Acerbate