What is default directory of File.Open?

Question

I have this code:

Stream f = File.Open("data.majid", FileMode.OpenOrCreate, FileAccess.ReadWrite);

Where will be file created?

Decani

Don't use relative paths unless you are in total control of the working directory. Always safer to use an absolute path. The main exception is console apps where the working directory should be considered an input parameter to the program. – Duralumin

Answer 1

From the File.Open MSDN documentation:

The path parameter is permitted to specify relative or absolute path information. Relative path information is interpreted as relative to the current working directory. To obtain the current working directory, see GetCurrentDirectory.

Hesychast

Answer 2

Usually the directory where the process was started from. This is the current working directory.

From MSDN

The current directory is distinct from the original directory, which is the one from which the process was started.

Flapper

No it is not! Relative paths are resolved relative to the process working directory. End of story. – Duralumin

Answer 3

From MSDN;

The path parameter is permitted to specify relative or absolute path information. Relative path information is interpreted as relative to the current working directory. To obtain the current working directory, see GetCurrentDirectory.

Check out Directory.GetCurrentDirectory

The current directory is distinct from the original directory, which is the one from which the process was started.

Varnish

Answer 4

it will store in current directory . that your application will run

e.g :

if you call Directory.GetCurrentDirectory(); it will return :

"C:\Program Files\Common Files\Microsoft Shared\DevServer\10.0"

Nomination

Answer 5

Additionally:

• the working directory can be changed in VisualStudio project settings Project | Properties | Debug

• if you create a shortcut to the application for a user you can specify the "Start in" property

Cupp