With Swift 4 you could easily make your own using a generic struct:
struct BidiMap<F:Hashable,T:Hashable>
{
private var _forward : [F:T]? = nil
private var _backward : [T:F]? = nil
var forward:[F:T]
{
mutating get
{
_forward = _forward ?? [F:T](uniqueKeysWithValues:_backward?.map{($1,$0)} ?? [] )
return _forward!
}
set { _forward = newValue; _backward = nil }
}
var backward:[T:F]
{
mutating get
{
_backward = _backward ?? [T:F](uniqueKeysWithValues:_forward?.map{($1,$0)} ?? [] )
return _backward!
}
set { _backward = newValue; _forward = nil }
}
init(_ dict:[F:T] = [:])
{ forward = dict }
init(_ values:[(F,T)])
{ forward = [F:T](uniqueKeysWithValues:values) }
subscript(_ key:T) -> F?
{ mutating get { return backward[key] } set{ backward[key] = newValue } }
subscript(_ key:F) -> T?
{ mutating get { return forward[key] } set{ forward[key] = newValue } }
subscript(to key:T) -> F?
{ mutating get { return backward[key] } set{ backward[key] = newValue } }
subscript(from key:F) -> T?
{ mutating get { return forward[key] } set{ forward[key] = newValue } }
var count:Int { return _forward?.count ?? _backward?.count ?? 0 }
}
var bd = BidiMap( [1:"A", 2:"B", 3:"C"] )
bd[1] // "A"
bd["B"] // 2
bd[4] = "D"
bd[to:"D"] // 4
bd[from:4] // "D"
var int2int = BidiMap( [1:2, 5:3] )
int2int[from:1] // 2
int2int[to:3] // 5
[EDIT] improved performance a bit by delaying rebuilding of mirror dictionary until it is actually referenced.