Using Haskell's Parsec to parse a ByteString

Question

I've managed to use Parsec to parse a String, but cannot manage to do the same with a ByteString.

How can I make Parsec work with ByteStrings without manually converting them to Strings?

I get the feeling this isn't hard to accomplish. Am I wrong? (I'm new to Haskell. ^^)

Thanks!

Hunk

Based on [the other question][1] you asked, you should learn to read the documentation of the library you're using. It's available on Hackage. [1]: #2087342 – Heuser

Answer 1

Just import the Parser type from Text.Parsec.ByteString or Text.Parsec.ByteString.Lazy, instead of from Text.Parsec.String.

Vogt

What is numbers in Text.Parsec.ByteString.Lazy(hackage.haskell.org/packages/archive/parsec/3.0.0/doc/html/…)? – Crenulation

see (#15455584 for where to go from here – Lachesis

Answer 2

the answer actually depends on the version of Parsec you are using. If you are using version 3.0 or later then yes. For version 2.x.x I don't think you can.

http://hackage.haskell.org/packages/archive/parsec/3.0.1/doc/html/Text-Parsec-ByteString.html

Cheers

edit: The Parsec that STH suggest (Text.Parsec.ByteString) is actually version 3.0 the previous version 2.x.x is located in Text.ParserCombinators.Parsec.

Mra

Oh, then I seem to currently lack the newest version, and have been using the older one. I will upgrade. Thank you both! – Hunk

Answer 3

import Text.Parsec.ByteString ()

will give you the instance

forall m. Stream ByteString m Char

hence if you use, instead of Parser a:

p ::  Stream s m Char => ParsecT s u m a

Pyridine

were you trying to explain how to get Word8 instead of Char, by any chance. I can't figure that out. – Endora