I am trying to convert a long filename to a short filename (8.3) on Windows.
A batch-file with a command line argument works as intended:
short.bat:
@echo OFF
echo %~s1
calling short.bat C:\Documents and Settings\User\NTUSER.DAT
returns C:\DOCUM~1\USER\NTUSER.DAT
However, I don't like having an extra .bat-file for this. I would rather call cmd.exe
with the whole command from a ruby script.
How can I do this?
As an intermediate step I tried to hardcode the path in the batch-file, but that does not work:
short1.bat:
@echo OFF
SET filename="C:\Documents and Settings\User\NTUSER.DAT"
echo %filename%
echo %~sfilename%
echo %filename%
works, but echo %~sfilename%
gives the following error:
The following usage of the path operator in batch-parameter
substitution is invalid: %~sfilename%
For valid formats type CALL /? or FOR /?
If short1.bat works, how can I convert this into a one-liner that can be called with cmd.exe \c ...
?
There is another question (how to get DOS path instead of Windows path), however that one is specifically asking for the path of the current directory.
%filename:~s%
(similar style to the substring notation,%filename:~0,1%
). If that works, I'll make an answer of it. – Sputnik