How to subset a vector, based on the condition "contains" a character?

Question

If I have a vector:

Months = month.abb[1:12]

I want to extract all the months that start with Letter J (in this case, Jan, Jun, and Jul).

1. Is there a wildcard character, like * in Excel, which lists all elements of vectors which you search for J*?

2. How do I extract elements that start with either letter 'M' or 'A'. The expected output would be Mar,May,Apr,Aug?

Baa

Answer 1

Try:

 grep("^J", Months,value=TRUE)
 #[1] "Jan" "Jun" "Jul"

grep("^A|^M", Months,value=TRUE)
#[1] "Mar" "Apr" "May" "Aug"

Lamppost

Perfect. Worked absolutely flawless. Cheers mate ! – Baa

Answer 2

You'll find the glob2rx function helpful for converting wildcard constructions to regular expressions:

> glob2rx("J*")
[1] "^J"
> grep(glob2rx("J*"), Months, value=TRUE)
[1] "Jan" "Jun" "Jul"

Regain

Thank you for bringing glob2rx to our attention. Are there other tools in base R that help people create regexes correctly? – Bedspread

@user2583119 There aren't any other similar functions that I know of. – Regain

Answer 3

If you happen to have stringr loaded you could do:

library(stringr)

str_subset(Months, "^J")
[1] "Jan" "Jun" "Jul"

Cohesion