How to return a file using Web API?
Asked Answered
M

8

134

I am using ASP.NET Web API.
I want to download a PDF with C# from the API (that the API generates).

Can I just have the API return a byte[]? and for the C# application can I just do:

byte[] pdf = client.DownloadData("urlToAPI");? 

and

File.WriteAllBytes()?
Murray answered 20/6, 2012 at 18:7 Comment(5)
"the Web API"? What exactly do you mean? Please read tinyurl.com/so-hints and edit your question.Sward
@JonSkeet: The Web API is a new feature in the latest version of ASP.NET. See asp.net/whitepapers/mvc4-release-notes#_Toc317096197Sideways
@Robert: Thanks - the tag makes it clearer, although referring to "the ASP.NET Web API" would have been clearer still. Partly MS's fault for a rubbishly generic name too :)Sward
blogs.msdn.com/b/codefx/archive/2012/02/23/…Sideways
Anyone who lands wanting to return the stream via web api and IHTTPActionResult then see here: nodogmablog.bryanhogan.net/2017/02/…Benzoate
T
200

Better to return HttpResponseMessage with StreamContent inside of it.

Here is example:

public HttpResponseMessage GetFile(string id)
{
    if (String.IsNullOrEmpty(id))
        return Request.CreateResponse(HttpStatusCode.BadRequest);

    string fileName;
    string localFilePath;
    int fileSize;

    localFilePath = getFileFromID(id, out fileName, out fileSize);
       
    HttpResponseMessage response = new HttpResponseMessage(HttpStatusCode.OK);
    response.Content = new StreamContent(new FileStream(localFilePath, FileMode.Open, FileAccess.Read));
    response.Content.Headers.ContentDisposition = new System.Net.Http.Headers.ContentDispositionHeaderValue("attachment");
    response.Content.Headers.ContentDisposition.FileName = fileName;
    response.Content.Headers.ContentType = new MediaTypeHeaderValue("application/pdf");

    return response;
}

UPDATE from comment by patridge: Should anyone else get here looking to send out a response from a byte array instead of an actual file, you're going to want to use new ByteArrayContent(someData) instead of StreamContent (see here).

Trunks answered 20/6, 2012 at 18:20 Comment(10)
First thing - this code will cause an exception since you're newing up two FileStream objects pointed at the same file. Second thing is that you do not want to use a "Using" statement, because as soon as the variable goes out of scope, .NET will dispose it and you'll get error messages about the underlying connection being closed.Extract
Should anyone else get here looking to send out a response from a byte array instead of an actual file, you're going to want to use new ByteArrayContent(someData) instead of StreamContent (see here).Diffractive
You may also want to override the base dispose() so you can handle your resources correctly when the framework calls it.Lengthen
@patridge: Is ByteArrayContent better than response.BinaryWrite?Adequacy
@IsaacKleinman I'm not sure. I haven't used Response.BinaryWrite. I'm guessing it would be throwing bytes at the stream directly rather than managing content using the Web API pipeline you have in place. If you have other processing steps in that API pipeline that need to run on the content before it heads down the wire, you may want to stick with ByteArrayContent. Best I can offer is to suggest you see what works best for your situation.Diffractive
What is the fileSize variable used for in the above code? Should/could this be sent in the response headers?Crossbred
This was a very helpful answer, but a user reported not being able to open pdf files returned to the client in this manner using Firefox. The files would open in Firefox as "filename.pdf.htm", which would cause the file not to open properly. Chrome, IE, Edge all worked fine. I found the solution was that you should also set the ContentType like this: response.Content.Headers.ContentType = new MediaTypeHeaderValue("application/pdf");Mopey
@Mopey Updated code accordingly to your commentTrunks
I would like to point out that the correct MediaTypeHeaderValue is crucial and to get it dynamic if you have different file types you can do like this. (where fileName is a string and has a file type ending like .jpg, .pdf, docx etc..) var contentType = MimeMapping.GetMimeMapping(fileName); response.Content.Headers.ContentType = new MediaTypeHeaderValue(contentType);Mcclees
Does the FileStream get disposed automatically?Groggery
E
45

Just a note for .Net Core: We can use the FileContentResult and set the contentType to application/octet-stream if we want to send the raw bytes. Example:

[HttpGet("{id}")]
public IActionResult GetDocumentBytes(int id)
{
    byte[] byteArray = GetDocumentByteArray(id);
    return new FileContentResult(byteArray, "application/octet-stream");
}
Expeller answered 3/7, 2019 at 17:55 Comment(4)
This works great, Also if you wanna control the file name there is a property on FileContentResult called FileDownloadName to specify the filenameBackdate
@Backdate ah didn't know that. Thanks for the comment.Expeller
Thats it, thanks. Also comment from weeksdev is very useful.Mertens
Thanks. This actually works for .NET Framework 4.8 as well.Laubin
A
44

I made the follow action:

[HttpGet]
[Route("api/DownloadPdfFile/{id}")]
public HttpResponseMessage DownloadPdfFile(long id)
{
    HttpResponseMessage result = null;
    try
    {
        SQL.File file = db.Files.Where(b => b.ID == id).SingleOrDefault();

        if (file == null)
        {
            result = Request.CreateResponse(HttpStatusCode.Gone);
        }
        else
        {
            // sendo file to client
            byte[] bytes = Convert.FromBase64String(file.pdfBase64);


            result = Request.CreateResponse(HttpStatusCode.OK);
            result.Content = new ByteArrayContent(bytes);
            result.Content.Headers.ContentDisposition = new System.Net.Http.Headers.ContentDispositionHeaderValue("attachment");
            result.Content.Headers.ContentDisposition.FileName = file.name + ".pdf";
        }

        return result;
    }
    catch (Exception ex)
    {
        return Request.CreateResponse(HttpStatusCode.Gone);
    }
}
Appliance answered 25/8, 2015 at 18:49 Comment(3)
This actually answers the questionNeedlewoman
This would not be a good idea with large files since it loads the entire image into memory. The stream option is better.Nixie
@PaulReedy Perfect... but in a lot of cases, you don't need to deal with large files. But I totally agree with your point!Fellowman
L
22

Example with IHttpActionResult in ApiController.

[HttpGet]
[Route("file/{id}/")]
public IHttpActionResult GetFileForCustomer(int id)
{
    if (id == 0)
      return BadRequest();

    var file = GetFile(id);

    IHttpActionResult response;
    HttpResponseMessage responseMsg = new HttpResponseMessage(HttpStatusCode.OK);
    responseMsg.Content = new ByteArrayContent(file.SomeData);
    responseMsg.Content.Headers.ContentDisposition = new System.Net.Http.Headers.ContentDispositionHeaderValue("attachment");
    responseMsg.Content.Headers.ContentDisposition.FileName = file.FileName;
    responseMsg.Content.Headers.ContentType = new MediaTypeHeaderValue("application/pdf");
    response = ResponseMessage(responseMsg);
    return response;
}

If you don't want to download the PDF and use a browsers built in PDF viewer instead remove the following two lines:

responseMsg.Content.Headers.ContentDisposition = new System.Net.Http.Headers.ContentDispositionHeaderValue("attachment");
responseMsg.Content.Headers.ContentDisposition.FileName = file.FileName;
Ladanum answered 29/12, 2017 at 22:32 Comment(2)
@ElbertJohnFelipe Yes, you get the file with var file = GetFile(id);. file.SomeData is a Byte Array (byte[]) and file.FileNameis string.Ladanum
Thank you for your post. 'HttpResponseMessage' didn't work for me inside an ApiController, so you saved me.Hanan
G
3

You Can try , HttpClient for Download file from another side and same time you can pass as File Result

 [HttpGet]
    [Route("api/getFile")]
    public async  Task<FileResult> GetFile(string Param1,string Param2)
    {
        try
        {
            Stream stream = null;
            string strURL = @"File URL";
            HttpClient client = new HttpClient();
            HttpResponseMessage httpResponse = await client.GetAsync(strURL);
            Stream streamToReadFrom = await httpResponse.Content.ReadAsStreamAsync();
            return File(streamToReadFrom, "{MIME TYPE}");

        }
        catch (Exception ex)
        {

            throw ex;
        }
        finally
        { 
        
        }
    }
Grote answered 3/1, 2022 at 11:36 Comment(0)
A
2

I've been wondering if there was a simple way to download a file in a more ... "generic" way. I came up with this.

It's a simple ActionResult that will allow you to download a file from a controller call that returns an IHttpActionResult. The file is stored in the byte[] Content. You can turn it into a stream if needs be.

I used this to return files stored in a database's varbinary column.

    public class FileHttpActionResult : IHttpActionResult
    {
        public HttpRequestMessage Request { get; set; }

        public string FileName { get; set; }
        public string MediaType { get; set; }
        public HttpStatusCode StatusCode { get; set; }

        public byte[] Content { get; set; }

        public Task<HttpResponseMessage> ExecuteAsync(CancellationToken cancellationToken)
        {
            HttpResponseMessage response = new HttpResponseMessage(StatusCode);

            response.StatusCode = StatusCode;
            response.Content = new StreamContent(new MemoryStream(Content));
            response.Content.Headers.ContentDisposition = new ContentDispositionHeaderValue("attachment");
            response.Content.Headers.ContentDisposition.FileName = FileName;
            response.Content.Headers.ContentType = new MediaTypeHeaderValue(MediaType);

            return Task.FromResult(response);
        }
    }
Ambi answered 2/3, 2020 at 15:9 Comment(1)
A brief explanation of how your code fixes the OP's problem(s) would enhance the quality of your answer.Kalikow
U
1

Another way to download file is to write the stream content to the response's body directly:

[HttpGet("pdfstream/{id}")]
public async Task  GetFile(long id)
{        
    var stream = GetStream(id);
    Response.StatusCode = (int)HttpStatusCode.OK;
    Response.Headers.Add( HeaderNames.ContentDisposition, $"attachment; filename=\"{Guid.NewGuid()}.pdf\"" );
    Response.Headers.Add( HeaderNames.ContentType, "application/pdf"  );            
    await stream.CopyToAsync(Response.Body);
    await Response.Body.FlushAsync();           
}
Uxorious answered 1/10, 2020 at 6:55 Comment(0)
E
0

My attempt works as:

public HttpResponseMessage GetFileFromPath2(string guid)
        {
            var response = new HttpResponseMessage();            
            MemoryStream memoryStream = new MemoryStream();
            var path = "C:\test";
            if (_fileHelper.ExtistFileFromPath(path, guid))
            {
                        memoryStream = new MemoryStream(File.ReadAllBytes(Path.Combine(path, guid)));

                        response.StatusCode = HttpStatusCode.OK;
                        response.Content = new StreamContent(memoryStream);
                        
                        response.Content.Headers.ContentDisposition = new ContentDispositionHeaderValue("attachment") { FileName = guid };
                        response.Content.Headers.ContentType = new MediaTypeHeaderValue("application/octet-stream");
                        response.Headers.AcceptRanges.Add("bytes");
            }
            else
            {
                response.StatusCode = HttpStatusCode.NoContent;
                response.Content = new StringContent("File not found");
            }

            return response;
        }
Elaboration answered 3/11, 2023 at 13:18 Comment(0)

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