'Expected String or Unicode' when reading JSON with Pandas
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I try to read an Openstreetmaps API output JSON string, which is valid.

I am using following code:

import pandas as pd
import requests

# Links unten
minLat = 50.9549
minLon = 13.55232

# Rechts oben
maxLat = 51.1390
maxLon = 13.89873

osmrequest = {'data': '[out:json][timeout:25];(node["highway"="bus_stop"](%s,%s,%s,%s););out body;>;out skel qt;' % (minLat, minLon, maxLat, maxLon)}
osmurl = 'http://overpass-api.de/api/interpreter'
osm = requests.get(osmurl, params=osmrequest)

osmdata = osm.json()

osmdataframe = pd.read_json(osmdata)

which throws following error:

---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
<ipython-input-66-304b7fbfb645> in <module>()
----> 1 osmdataframe = pd.read_json(osmdata)

/Users/paul/anaconda/lib/python2.7/site-packages/pandas/io/json.pyc in read_json(path_or_buf, orient, typ, dtype, convert_axes, convert_dates, keep_default_dates, numpy, precise_float, date_unit)
    196         obj = FrameParser(json, orient, dtype, convert_axes, convert_dates,
    197                           keep_default_dates, numpy, precise_float,
--> 198                           date_unit).parse()
    199 
    200     if typ == 'series' or obj is None:

/Users/paul/anaconda/lib/python2.7/site-packages/pandas/io/json.pyc in parse(self)
    264 
    265         else:
--> 266             self._parse_no_numpy()
    267 
    268         if self.obj is None:

/Users/paul/anaconda/lib/python2.7/site-packages/pandas/io/json.pyc in _parse_no_numpy(self)
    481         if orient == "columns":
    482             self.obj = DataFrame(
--> 483                 loads(json, precise_float=self.precise_float), dtype=None)
    484         elif orient == "split":
    485             decoded = dict((str(k), v)

TypeError: Expected String or Unicode

How to modify the request or Pandas read_json, to avoid an error? By the way, what's the problem?

Triplett answered 20/7, 2014 at 7:41 Comment(0)
L
13

If you print the json string to a file,

content = osm.read()
with open('/tmp/out', 'w') as f:
    f.write(content)

you'll see something like this:

{
  "version": 0.6,
  "generator": "Overpass API",
  "osm3s": {
    "timestamp_osm_base": "2014-07-20T07:52:02Z",
    "copyright": "The data included in this document is from www.openstreetmap.org. The data is made available under ODbL."
  },
  "elements": [

{
  "type": "node",
  "id": 536694,
  "lat": 50.9849256,
  "lon": 13.6821776,
  "tags": {
    "highway": "bus_stop",
    "name": "Niederhäslich Bergmannsweg"
  }
},
...]}

If the JSON string were to be converted to a Python object, it would be a dict whose elements key is a list of dicts. The vast majority of the data is inside this list of dicts.

This JSON string is not directly convertible to a Pandas object. What would be the index, and what would be the columns? Surely you don't want [u'elements', u'version', u'osm3s', u'generator'] to be the columns, since almost all the information is in the elements list-of-dicts.

But if you want the DataFrame to consist of the data only in the elements list-of-dicts, then you'd have to specify that, since Pandas can't make that assumption for you.

Further complicating things is that each dict in elements is a nested dict. Consider the first dict in elements:

{
  "type": "node",
  "id": 536694,
  "lat": 50.9849256,
  "lon": 13.6821776,
  "tags": {
    "highway": "bus_stop",
    "name": "Niederhäslich Bergmannsweg"
  }
}

Should ['lat', 'lon', 'type', 'id', 'tags'] be the columns? That seems plausible, except that the tags column would end up being a column of dicts. That's usually not very useful. It would be nicer perhaps if the keys inside the tags dict were made into columns. We can do that, but again we have to code it ourselves since Pandas has no way of knowing that's what we want.


import pandas as pd
import requests
# Links unten
minLat = 50.9549
minLon = 13.55232

# Rechts oben
maxLat = 51.1390
maxLon = 13.89873

osmrequest = {'data': '[out:json][timeout:25];(node["highway"="bus_stop"](%s,%s,%s,%s););out body;>;out skel qt;' % (minLat, minLon, maxLat, maxLon)}
osmurl = 'http://overpass-api.de/api/interpreter'
osm = requests.get(osmurl, params=osmrequest)

osmdata = osm.json()
osmdata = osmdata['elements']
for dct in osmdata:
    for key, val in dct['tags'].iteritems():
        dct[key] = val
    del dct['tags']

osmdataframe = pd.DataFrame(osmdata)
print(osmdataframe[['lat', 'lon', 'name']].head())

yields

         lat        lon                        name
0  50.984926  13.682178  Niederhäslich Bergmannsweg
1  51.123623  13.782789                Sagarder Weg
2  51.065752  13.895734     Weißig, Einkaufszentrum
3  51.007140  13.698498          Stuttgarter Straße
4  51.010199  13.701411          Heilbronner Straße
Limp answered 20/7, 2014 at 8:21 Comment(3)
Great explanation!! I understand this perfectly, but couldn't solve the riddle for my own. Thanks! In the line osmdata = json.loads(osm.read()) might be something not correct, because I get: AttributeError: 'Response' object has no attribute 'read'Triplett
It have to be osmdata = json.loads(osm.content)Triplett
@Balzer82: My version of requests was too old; the API has changed since then. I've updated by requests and will edit the code above.Limp

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