I am looking for an easy way to sort NameValueCollection on the basis of key - it should not be a performance heavy though.
Is there any easy way to sort NameValueCollection on the basis of key in C#?
Asked Answered
Start with SortedDictionary<string,string>
or SortedList<string,string>
and you're already there...
If you need the multiple items per key, then consider a SortedDictionary<string,List<string>>
. There are ways to simplify addition etc with extension methods - it needn't be scary.
Note also that NameValueCollection
is case-insensitive, so you might need to use one of the insensitive comparisons - for example:
Dictionary<string,string> data = new Dictionary<string,string>(
StringComparer.InvariantCultureIgnoreCase);
(edit) here's an example of using an extension method to populate multiple values against a single key in C# 3.0:
static void Main()
{
var data = new Dictionary<string, List<string>>(
StringComparer.InvariantCultureIgnoreCase);
data.Add("abc", "def");
data.Add("abc", "ghi");
}
static void Add<TKey, TValue>(this IDictionary<TKey, List<TValue>> lookup,
TKey key, TValue value)
{
List<TValue> list;
if (!lookup.TryGetValue(key, out list))
{
list = new List<TValue>();
lookup.Add(key, list);
}
list.Add(value);
}
Here's a brute force hack that I'm not too proud of, but it works if you need something quick and dirty.
public static void Sort(this NameValueCollection nameValueCollection)
{
// Create a temporary collection the same size as the original
NameValueCollection tempNameValueCollection = new NameValueCollection(nameValueCollection.Count);
// Sort the keys
string[] keys = nameValueCollection.AllKeys;
Array.Sort(keys);
foreach (string key in keys)
{
// Sort the values
string[] values = nameValueCollection[key].Split(',');
Array.Sort(values);
// Add each value to the temporary collection
foreach (string value in values)
{
tempNameValueCollection.Add(key, value);
}
}
// Clear the original collection
nameValueCollection.Clear();
// Add the sorted entries back
nameValueCollection.Add(tempNameValueCollection);
}
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