sed substitution with Bash variables
Asked Answered
W

6

87

I am trying to change the values in a text file using sed in a Bash script with the line,

sed 's/draw($prev_number;n_)/draw($number;n_)/g' file.txt > tmp

This will be in a for loop. Why is it not working?

Washedout answered 6/10, 2011 at 21:11 Comment(0)
A
120

Variables inside ' don't get substituted in Bash. To get string substitution (or interpolation, if you're familiar with Perl) you would need to change it to use double quotes " instead of the single quotes:

# Enclose the entire expression in double quotes
$ sed "s/draw($prev_number;n_)/draw($number;n_)/g" file.txt > tmp

# Or, concatenate strings with only variables inside double quotes
# This would restrict expansion to the relevant portion
# and prevent accidental expansion for !, backticks, etc.
$ sed 's/draw('"$prev_number"';n_)/draw('"$number"';n_)/g' file.txt > tmp

# A variable cannot contain arbitrary characters
# See link in the further reading section for details
$ a='foo
bar'
$ echo 'baz' | sed 's/baz/'"$a"'/g'
sed: -e expression #1, char 9: unterminated `s' command

Further Reading:

Atonality answered 6/10, 2011 at 21:16 Comment(3)
Maybe also mention that if the variable contains slashes, you need to use a different delimiter which doesn't occur in the string (or backslash-escape every occurrence of the delimiter). The slash is a common default for s but you can use any punctuation character; sed "s%draw($prev_number;n_)%draw($number;n_)%g" file.txt or s#from#to#g or s_from_to_g etc.Tactician
it doesn't work if the variable contains new-lines ("\n")Sundin
but it did once escaped (for my use cases) also slashes: changelogEscaped=$(sed -e 's%\/%\\/%g; $!a\'$'\n''\\n' <<<"$changelog" | tr -d '\n') Thanks for the link above.Sundin
R
17

Variables within single quotes are not expanded, but within double quotes they are. Use double quotes in this case.

sed "s/draw($prev_number;n_)/draw($number;n_)/g" file.txt > tmp

You could also make it work with eval, but don’t do that!!

Refutative answered 6/10, 2011 at 21:15 Comment(1)
Thanks that worked. Would you mind explaining what you mean by expanded? My intuition tells me that it should be something like, variable substituted. Also why not use eval?Washedout
H
4

This may help:

sed "s/draw($prev_number;n_)/draw($number;n_)/g" 
Howardhowarth answered 6/10, 2011 at 21:13 Comment(0)
A
1

You can use variables like below. Like here, I wanted to replace hostname i.e., a system variable in the file. I am looking for string look.me and replacing that whole line with look.me=<system_name>

sed -i "s/.*look.me.*/look.me=`hostname`/"

You can also store your system value in another variable and can use that variable for substitution.

host_var=`hostname`

sed -i "s/.*look.me.*/look.me=$host_var/"


Input file:

look.me=demonic

Output of file (assuming my system name is prod-cfm-frontend-1-usa-central-1):

look.me=prod-cfm-frontend-1-usa-central-1
Asiaasian answered 16/6, 2016 at 19:37 Comment(0)
H
1

I needed to input github tags from my release within github actions. So that on release it will automatically package up and push code to artifactory.

Here is how I did it. :)

  - name: Invoke build
    run: |
      # Gets the Tag number from the release
      TAGNUMBER=$(echo $GITHUB_REF | cut -d / -f 3)
      
      # Setups a string to be used by sed
      FINDANDREPLACE='s/${GITHUBACTIONSTAG}/'$(echo $TAGNUMBER)/
      
      # Updates the setup.cfg file within version number
      sed -i $FINDANDREPLACE setup.cfg
      
      # Installs prerequisites and pushes 
      pip install -r requirements-dev.txt
      invoke build

Retrospectively I wish I did this in python with tests. However it was fun todo some bash.

Harping answered 16/3, 2021 at 21:48 Comment(0)
T
1

Another variant, using printf:

SED_EXPR="$(printf -- 's/draw(%s;n_)/draw(%s;n_)/g' $prev_number $number)"

sed "${SED_EXPR}" file.txt

or in one line:

sed "$(printf -- 's/draw(%s;n_)/draw(%s;n_)/g' $prev_number $number)" file.txt

Using printf to build the replacement expression should be safe against all kinds of weird things, which is why I like this variant.

Therapeutics answered 31/1, 2023 at 17:53 Comment(0)

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