How to generate a Unique id, flutter

Question

I am making a todo app with notifications and am using flutter local notifications plugin, How do I generate a unique integer as id for a specific todo so that I can also cancel notification of that specific todo using that unique integer.

Trews

Answer 1

You can use UniqueKey().hashCode() to get a unique int.
For example:

final notificationId = UniqueKey().hashCode()
// or you can use DateTime.now().millisecondsSinceEpoch
...

Numerical

I knew Unique key wouldn't work but forgot to try hash code, thanks anyways – Trews

You don't need to put () after .hashCode — it's a property – Mccue

Answer 2

I mention some of methods how you can get unique id :-

use time stamps like this

DateTime.now().millisecondsSinceEpoch;

In year 2020 you can do UniqueKey();

Note

A key that is only equal to itself.

This cannot be created with a const constructor because that implies that all instantiated keys would be the same instance and therefore not be unique.

https://api.flutter.dev/flutter/widgets/UniqueKey-class.html

can use xid package which is lock free and has a Unicity guaranteed for 24 bits unique ids per second and per host/process

import 'package:xid/xid.dart';

void main() {
  var xid = Xid();
  print('generated id: $xid');

}

Beshore

Uuid does not return an int as required by the flutter notifications plugin. – Numerical

okay I wil update my answer – Beshore

Answer 3

You can use the following class:

class UuidUtil {
  static int get uuid => DateTime.now().microsecondsSinceEpoch;
}

And access it by:

final id = UuidUtil.uuid;

Sparling

Answer 4

To generate a unique integer ID you can use this code

import 'package:id_gen/id_gen_helpers.dart';

final idInt = genUuid.hash();                    // 2^64 native
final idIntShort = genUuid.hash() & 0xFFFFFFFF;  // 2^32
final idIntShortest = genUuid.hash() & 0xFFFF;   // 2^16

from the lightweight and well-tested Dart package https://pub.dev/packages/id_gen

Historical

Answer 5

You can used UUID package here

import 'package:uuid/uuid.dart';

 var uuid = Uuid();
 print(uuid.v1());  

 print(uuid.v4()); 

Or refer this also

Arrington

This will not give an int as required by the flutter notifications plugin. – Numerical

Answer 6

You can use this package: http://pub.dartlang.org/packages/uuid

import 'package:uuid/uuid.dart';

// Create uuid object
var uuid = Uuid();

// Generate a v1 (time-based) id
uuid.v1(); // -> '6c84fb90-12c4-11e1-840d-7b25c5ee775a'

// Generate a v4 (random) id
uuid.v4(); // -> '120ec61a-a0f2-4ac4-8393-c866d813b8d1'

Ambrosio

Uuid does not return an int as required by the flutter notifications plugin. – Numerical