Renaming files by reformatting existing filenames - placeholders in replacement strings used with the -replace operator

Question

I have a few video file like this: VideoName_s01e01.mp4 where the season and episodes are variables. I want to add an underscore ("_") between the s?? and e??.

I have been using powershell for renaming purposes, I have a starting point:

GCI $path -filter '*_s??e??*' -rec |  Ren -new { $_.name -replace '_s[0-9][0-9]', '_s[0-9]_[0-9]_' } -passthru    

This actually renamed my files VideoName_s[0-9]_e[0-9].mp4.

Basically, I am looking for the characters s??e?? I just don't know how to make them variables in the replace section.

I think the best method would be:

1. Find the position of e??s?? (let's call it X).
2. split the string at X-3.
3. concatenate the string with a "_" in the middle.

Beckett

Answer 1

Martin Brandl's answer provides an elegant and effective solution, but it's worth digging deeper:

PowerShell's -replace operator (... -replace <search>[, <replace>]):

• Takes a regular expression as its first operand, <search> (the search expression), and invariably matches globally, i.e., it replaces all matches.

  • 'bar' -replace '[ra]', '@' -> 'b@@'
  • If you want to replace a literal string, you must either individually \-escape any regex metacharacters (e.g. .) or use the result from a [regex]::Escape() call:
    • 'bar.none' -replace '\.', '-' -> 'bar-none'
    • 'bar.none' -replace [regex]::Escape('.'), '-' -> 'bar-none'

• Specifying a replacement expression, <replace>, is optional, in which case the empty string is substituted for what <search> matched, resulting in its effective removal.

  • 'bar' -replace '[ra]' -> 'b'

• If <replace> is specified, it supports two forms:

  • v6.1+ (PowerShell Core only): A script block ({ ... }) as the replacement operand, which offers fully dynamic calculation of the replacement string on a per-match basis:

    • 'Level 41' -replace '\d+', { 1 + $_.Value } -> 'Level 42'

  • A string containing an expression that can reference what the regular expression captured (and didn't capture) - such as $& to refer to what was matched - explained in detail below.

    • 'bar' -replace '[ra]', '{$&}' -> 'b{a}{r}'

• -replace matches case-insensitively (and can also be written as -ireplace); to perform case-sensitive matching, use the form -creplace.

---

The "replacement language" for referencing regex captures in a string-typed <replace> operand is itself not a regular expression - no matching happens there, only references to the results of the regex matching are supported, via $-prefixed placeholders that are not to be confused with PowerShell variables.

• PowerShell's documentation (now) briefly explains the syntax of replacement strings in its conceptual about_Comparison_Operators help topic.

• For the full picture, refer to the Substitutions in Regular Expressions .NET framework help topic, which is applicable because PowerShell's -replace uses the Regex.Replace() method behind the scenes.

For convenience, here are the references supported in the <replace> string (excerpted from the page linked above, with emphasis and annotations added):

• $number (e.g., $1) ... Includes the last substring matched by the capture group that is identified by the 1-based number in the replacement string:

  • Including (...), a parenthesized subexpression, in the regex implicitly creates a capture group (capturing group). By default, such capture groups are unnamed and must be referenced by their 1-based (decimal) index reflecting the order in which they appear in the regex, so that $1 refers to what the 1st group in your regex captured, $2 to what the 2nd captured, ...

  • The form ${number} (e.g., ${1}) for disambiguation of the number is also supported (e.g., to make sure that $1 is recognized even if followed by, say, 000, use ${1}000).

  • Instead of relying on indices to refer to unnamed capture groups, you can name capture groups and refer to them by name - see next point.

  • If you're not interested in what the capture group matched, you can opt to ignore it by turning it into a non-capturing group with (?:...).

• ${name} ... Includes the last substring matched by the named capture group that is designated by (?<name>...) in the replacement string.

• $$ ... Includes a single "$" literal in the replacement string.

• $& ... Includes a copy of the entire match in the replacement string ($0 works too, even though it isn't directly documented).

• $` ... Includes the text of the input string before the match in the replacement string.

• $' ... Includes the text of the input string after the match in the replacement string.

• $+ ... Includes the last group captured in the replacement string. [This relieves you of the need to know the last group's specific index.]

• $_ ... Includes the entire input string in the replacement string.

Finally, note that:

• -replace invariably matches globally, so if the input string contains multiple matches, the replacements above apply to each match.

• It is generally preferable to use '...' (single quotes) for both the regex and the replacement string, because single-quoted strings are non-expanding (non-interpolating), and therefore avoid confusion with PowerShell's own up-front expansions of $-prefixed tokens and interpretation of ` chars.
  If you do need to include PowerShell variables or expressions, you have three options:

  • Use "..." (expandable strings) and `-escape $ instances that are meant for the regex engine; e.g., `$1 in the following example:
    'abc' -replace '(a)', "[`$1]-$HOME-"
    which yields something like [a]-C:\Users\jdoe-bc

  • Build your string from literal pieces and variable references using string concatenation (+); e.g.:
    'abc' -replace '(a)', ('[$1]-' + $HOME + '-')

  • Use -f, the string-formatting operator string concatenation; e.g.:
    'abc' -replace '(a)', ('[$1]-{0}-' -f $HOME)

• Given that you need to use $$ to escape a literal $ in the replacement string, use the following idiom to use a variable whose value you want to use literally:

  • ... -replace <search>, $var.Replace('$', '$$')
  • This relies on the [string]::Replace() method performing literal substring replacements.
    On a side note, this method is an alternative to -replace in simple cases, but note that it is case-sensitive by default.
  • Alternatively, use a nested -replace operation, but the syntax is tricky due to the escaping requirements:
    ... -replace <search>, ($var -replace '\$', '$$$$')

Genovevagenre

Answer 2

I highly recommend regex101.com for learning regex.

Something like this can work:

"VideoName_s01e01.mp4" -replace '(.*s)(\d+)(e.*)', '$1$2_$3'

Gives:

VideoName_s01_e01.mp4

Sandberg

Answer 3

-replace is using regex, not wildcards. Thus you have to change the replace to:

-replace '_s([0-9]{1,2})e([0-9]{1,2})', '_s$1_e$2_'

Vories

Answer 4

regex is the better solution, i propose other with formating number and use Template

$exampleoffile = @"
namev1_s01e01.mp4
namvev2_s03e02.mp4
VideoName_s20e15.mp4
VideoName_s15e1.mp4
VideoName_s1e16.avi
VideoName_s1e23.mv
"@

$template=@"
{file*:{prefix:Test1}_s{season:01}e{episode:01}{extension:.mp4}}
{file*:{prefix:1xxx}_s{season:100}e{episode:5}{extension:.mp4}}
{file*:{prefix:yyy3}_s{season:10}e{episode:02}{extension:.havi}}
"@



$exampleoffile | ConvertFrom-String -TemplateContent $template | 
% { "{0}_{1:D2}_e{2:D2}{3}" -f $_.file.prefix, [int]$_.file.season, [int]$_.file.episode, $_.file.extension }

Moneywort