getline(cin, aString) receiving input without another enter
Asked Answered
R

3

6

My code looks like this,

string aString;
cin >> aString;
cout << "This is what cin gets:" << aString << endl;
getline(cin, aString);
cout << "This is what getline(cin, <string>) gets:" << aString << endl;

Each time I ran it, I give inputs like, "12", I get "12" and "".

I am wondering why getline would received without user input.

I can understand when I enter something like "12 24", cin will get "12", and getline should get the rest. (Also, if one could answer, the space in between is treated as an end for cin, so why is it passed on to getline?)

Just starting out on string on C++ so please don't make it too hard. Thanks you.

Readership answered 23/2, 2012 at 19:5 Comment(1)
If you've already gotten the input there is nothing more to get unless there is more input ...Whig
C
12

When you mix standard stream extraction with getline, you will sometimes have getline return the empty string. The reason for this is that if you read input with >>, the newline character entered by the user to signal that they're done is not removed from the input stream. Consequently, when you call getline, the function will read the leftover newline character and hand back the empty string.

To fix this, either consistently use getline for your input, or use the ws stream manipulator to extract extra white space after a read:

cin >> value >> ws;

This will eat up the newline, fixing the problem.

Hope this helps!

Constitute answered 23/2, 2012 at 19:11 Comment(0)
E
8

this is what I get:

std::string str;
std::cin >> str;  //hello world
std::cout << str;  //hello

this is because the stream operator tokenizes on white space

std::string str;
std::getline(std::cin, str);  //hello world
std::cout << str;  //hello world

you get the full line, getline() works until it find the first end of line and returns that value as a string.

However when tokenizing, if there are characters (for example a '\n') left in the stream then these will be accessed when getline is called, you will need to clear the stream.

std::cin.ignore();
Entreat answered 23/2, 2012 at 19:10 Comment(1)
How to perform similar action as cin.ignore() if you are reading from a filestream? getline(inFile, str) also resturns empty if you read an int before it.Delative
O
1

"cin >> x" doesn't consume the newline character from the input stream, so the next line you retrieve with getline will contain an empty string. One way to solve this is to use getline to retrieve input line by line and use a stringstream to tokenize each line. After you've extracted all input from the stringstream, the key thing is to call stringstream::clear() to clear the EOF flag set on the stringstream to be able to reuse it later in the code.

Here's an example:

#include <iostream>
#include <sstream>
#include <string>

using namespace std;

int main() {
    string line;
    stringstream ss;
    getline(cin, line);
    ss << line;
    int x, y, z;
    //extract x, y, z and any overflow characters
    ss >> x >> y >> z >> line;
    ss.clear();
    //reuse ss after clearing the eof flag
    getline(cin, line);
    ss << line;
    //extract new fields, then clear, then reuse
    //...
    return 0;
}

Depending on the length of each input line, getting the whole line at a time and processing it in-memory is probably more efficient than doing console IO on every token you want to extract from the standard input.

Obala answered 23/2, 2012 at 20:37 Comment(0)

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