How can I parse the output of var_dump
in PHP to create an array?
Use var_export if you want a representation which is also valid PHP code
$a = array (1, 2, array ("a", "b", "c"));
$dump=var_export($a, true);
echo $dump;
will display
array (
0 => 1,
1 => 2,
2 =>
array (
0 => 'a',
1 => 'b',
2 => 'c',
),
)
To turn that back into an array, you can use eval, e.g.
eval("\$foo=$dump;");
var_dump($foo);
Not sure why you would want to do this though. If you want to store a PHP data structure somewhere and then recreate it later, check out serialize() and unserialize() which are more suited to this task.
Maybe you’re looking for var_export
that will give you a valid PHP expression of the passed value.
I had a similar problem : a long runing script produced at the end a vardump of large array. I had to parse it back somehow for further analyzis. My solution was like this:
cat log.stats |
sed 's/\[//g' |
sed 's/\]//g' |
sed -r 's/int\(([0-9]+)\)/\1,/g' |
sed 's/\}/\),/g' |
sed -r 's/array\([0-9]+\) \{/array(/g' >
log.stats.php
You can't. var_dump
just outputs text but doesn't return anything.
Perhaps you are trying to convert an object to an array? http://www.phpro.org/examples/Convert-Object-To-Array-With-PHP.html
var_export
creates the PHP code, which you can run through the eval
.
But I wonder, what is your idea?
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