Using SQL Server 2000, how can I get the first and last date of the current year?
Expected Output:
01/01/2012
and 31/12/2012
Using SQL Server 2000, how can I get the first and last date of the current year?
Expected Output:
01/01/2012
and 31/12/2012
SELECT
DATEADD(yy, DATEDIFF(yy, 0, GETDATE()), 0) AS StartOfYear,
DATEADD(yy, DATEDIFF(yy, 0, GETDATE()) + 1, -1) AS EndOfYear
The above query gives a datetime value for midnight at the beginning of December 31. This is about 24 hours short of the last moment of the year. If you want to include time that might occur on December 31, then you should compare to the first of the next year, with a <
comparison. Or you can compare to the last few milliseconds of the current year, but this still leaves a gap if you are using something other than DATETIME (such as DATETIME2):
SELECT
DATEADD(yy, DATEDIFF(yy, 0, GETDATE()), 0) AS StartOfYear,
DATEADD(yy, DATEDIFF(yy, 0, GETDATE()) + 1, -1) AS LastDayOfYear,
DATEADD(yy, DATEDIFF(yy, 0, GETDATE()) + 1, 0) AS FirstOfNextYear,
DATEADD(ms, -3, DATEADD(yy, DATEDIFF(yy, 0, GETDATE()) + 1, 0)) AS LastTimeOfYear
Other Periods
This approach has two nice aspects: good performance and it can easily be changed for other periods by replacing both occurrences of yy
(=year) with a different string:
yy, yyyy year
qq, q quarter
mm, m month
wk, ww week
(Be careful of weeks: the starting day depends on server settings.)
Tech Details
This works by figuring out the number of years since 1900 with DATEDIFF(yy, 0, GETDATE())
and then adding that to a date of zero = Jan 1, 1900. This can be changed to work for an arbitrary date by replacing the GETDATE()
portion or an arbitrary year by replacing the DATEDIFF(...)
function with "Year - 1900."
SELECT
DATEADD(yy, DATEDIFF(yy, 0, '20150301'), 0) AS StartOfYearForMarch2015,
DATEADD(yy, 2015 - 1900, 0) AS StartOfYearFor2015
Here's a fairly simple way;
SELECT DATEFROMPARTS(YEAR(GETDATE()), 1, 1) AS 'First Day of Current Year';
SELECT DATEFROMPARTS(YEAR(GETDATE()), 12, 31) AS 'End of Current Year';
It's not sexy, but it works.
You can get the current year using DATEPART
function, from the current date obtained using getUTCDate()
SELECT
'01/01/' + CONVERT(VARCHAR(4), DATEPART(yy, getUTCDate())),
'31/12/' + CONVERT(VARCHAR(4), DATEPART(yy, getUTCDate()))
DATETIME
using CONVERT
function, the dates should be in MM/dd/yyyy format. –
Huge DATETIME
instead of string and obviously that may not match the expected output as per the question. –
Huge yyyyMMdd
is unambiguous. –
Pavlov Another way: (Since SQL Server 2012)
SELECT
DATEFROMPARTS(YEAR(GETDATE()), 1, 1) FirstDay,
DATEFROMPARTS(YEAR(GETDATE()),12,31) LastDay
simply write:-
select convert (date,DATEADD(YEAR,DATEDIFF(YEAR,0,GETDATE()),0))
start date of the year.
select convert (date,DATEADD(YEAR, DATEDIFF(YEAR,0,GETDATE()) + 1, -1))
Every year has the 1 st as First date and 31 as the last date what you have to do is only attach the year to that day and month for example:-
SELECT '01/01/'+cast(year(getdate()) as varchar(4)) as [First Day],
'12/31/'+cast(year(getdate()) as varchar(4)) as [Last Day]
To get the first and the last day of the year, one can use the CONCAT
function. The resulting value may be cast to any type.
CONCAT(YEAR(Getdate()),'-01-01') FirstOfYear,
CONCAT(YEAR(GETDATE()),'-12-31') LastOfYear
The best way is to extract the current year then use concatenation like this :
SELECT CONCAT(year(now()), '-01-01') as start, -- fist day of current year
CONCAT(year(now()), '-31-12') as end; -- last day of current year
That gives you : start : 2020-01-01 and end : 2020-31-12
in date format.
For start date of current year:
SELECT DATEADD(DD,-DATEPART(DY,GETDATE())+1,GETDATE())
For end date of current year:
SELECT DATEADD(DD,-1,DATEADD(YY,DATEDIFF(YY,0,GETDATE())+1,0))
The best way to get First Date and Last Date of a year Is
SELECT CAST(CAST(YEAR(DATEADD(YEAR,-1,GETDATE())) AS VARCHAR) + '-' + '01' + '-' + '01' AS DATE) FIRST_DATE
SELECT CAST(CAST(YEAR(DATEADD(YEAR,-1,GETDATE())) AS VARCHAR) + '-' + '12' + '-' + '31' AS DATE) LAST_DATE
Check out this one:
select convert(varchar(12),(DateAdd(month,(Month(getdate())-1) * -1, DateAdd(Day,(Day(getdate())-1) * -1,getdate()))),103) as StartYear,
convert(varchar(12),DateAdd(month,12 - Month(getdate()), DateAdd(Day,(31 - Day(getdate())),getdate())),103) as EndYear
SELECT DATEADD(DD,-DATEPART(DY,GETDATE())+1,GETDATE())
print Cast('1/1/' + cast(datepart(yyyy, getdate()) as nvarchar(4)) as date)
It looks like you are interesting in performing an operation everything for a given year, if this is indeed the case, I would recommend to use the YEAR() function like this:
SELECT * FROM `table` WHERE YEAR(date_column) = '2012';
The same goes for DAY() and MONTH(). They are also available for MySQL/MariaDB variants and was introduced in SQL Server 2008 (so not for specific 2000).
In Microsoft SQL Server (T-SQL) this can be done as follows
--beginning of year
select '01/01/' + LTRIM(STR(YEAR(CURRENT_TIMESTAMP)))
--end of year
select '12/31/' + LTRIM(STR(YEAR(CURRENT_TIMESTAMP)))
CURRENT_TIMESTAMP - returns the sql server date at the time of execution of the query.
YEAR - gets the year part of the current time stamp.
STR , LTRIM - these two functions are applied so that we can convert this into a varchar that can be concatinated with our desired prefix (in this case it's either first date of the year or the last date of the year). For whatever reason the result generated by the YEAR function has prefixing spaces. To fix them we use the LTRIM function which is left trim.
If it reaches the 1st of Jan you might it to be still last years date.
select
convert(date, DATEADD(yy, DATEDIFF(yy, 0, DATEadd(day, -1,getdate())), 0), 103 ) AS StartOfYear,
convert(date, DATEADD(yy, DATEDIFF(yy, 0, DATEDIFF(day, -1,getdate()))+1, -1), 103 )AS EndOfYear
select to_date(substr(sysdate,1, 4) || '01/01'), to_date(substr(sysdate,1, 4) || '12/31')
from dual
Try this:
DATE_FORMAT(NOW(),'01/01/%Y')
DATE_FORMAT(NOW(),'31/12/%Y')
Msg 195, Level 15, State 10, Line 1 'NOW' is not a recognized function name.
–
Poplin ---Lalmuni Demos---
create table Users
(
userid int,date_of_birth date
)
---insert values---
insert into Users values(4,'9/10/1991')
select DATEDIFF(year,date_of_birth, getdate()) - (CASE WHEN (DATEADD(year, DATEDIFF(year,date_of_birth, getdate()),date_of_birth)) > getdate() THEN 1 ELSE 0 END) as Years,
MONTH(getdate() - (DATEADD(year, DATEDIFF(year, date_of_birth, getdate()), date_of_birth))) - 1 as Months,
DAY(getdate() - (DATEADD(year, DATEDIFF(year,date_of_birth, getdate()), date_of_birth))) - 1 as Days,
from users
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DATEADD(yy, DATEDIFF(yy, 0, GETDATE()), 0)
makes sense. But how about -1?DATEADD(yy, DATEDIFF(yy, 0, GETDATE()) + 1, -1)
, what is -1 represent? is it represent the day count since 01/01/1900 - which in this case -1 becomes 31/12/1899? – Potency