I am a beginner when it comes to programming but I was sure that one of the universal rules was that a program starts with Main(). I do not see one when I create a WPF project. Is Main() simply named something differently in WPF?
It is generated during build, but you can provide your own (disambiguating it in project-properties as necessary). Look in obj/debug for an app file; I have (courtesy of "C# 2010 Express") App.g.i.cs
with:
namespace WpfApplication1 {
/// <summary>
/// App
/// </summary>
[System.CodeDom.Compiler.GeneratedCodeAttribute("PresentationBuildTasks", "4.0.0.0")]
public partial class App : System.Windows.Application {
/// <summary>
/// InitializeComponent
/// </summary>
[System.Diagnostics.DebuggerNonUserCodeAttribute()]
public void InitializeComponent() {
#line 4 "..\..\..\App.xaml"
this.StartupUri = new System.Uri("MainWindow.xaml", System.UriKind.Relative);
#line default
#line hidden
}
/// <summary>
/// Application Entry Point.
/// </summary>
[System.STAThreadAttribute()]
[System.Diagnostics.DebuggerNonUserCodeAttribute()]
public static void Main() {
WpfApplication1.App app = new WpfApplication1.App();
app.InitializeComponent();
app.Run();
}
}
}
App.g.cs
, as well. But I tried to add to Main()
and every time I would rebuild my project, it would revert to what you have, here. Tried to create my own in another class, but Project Properties only finds MyProject.App, not the other class, so can't redirect it. –
Soiree App.xaml.cs
in visual studio. Use the navigation bar > Method drop down list > select Main
(greyed out). This takes you to App.g.i.cs
. –
Sthilaire The Main() method is created automatically. If you want to provide your own you have to (tested in VS2013, VS2017 and VS2019):
- Right-click App.xaml in the solution explorer, select Properties
- Change 'Build Action' to 'Page' (initial value is 'ApplicationDefinition')
Then just add a Main() method to App.xaml.cs. It could be like this:
[STAThread]
public static void Main()
{
var application = new App();
application.InitializeComponent();
application.Run();
}
Program.cs
class 2. add the code in this answer to Program.cs
3. in project properties, choose ProjectName.Program
as Startup object
–
Angularity It is generated during build, but you can provide your own (disambiguating it in project-properties as necessary). Look in obj/debug for an app file; I have (courtesy of "C# 2010 Express") App.g.i.cs
with:
namespace WpfApplication1 {
/// <summary>
/// App
/// </summary>
[System.CodeDom.Compiler.GeneratedCodeAttribute("PresentationBuildTasks", "4.0.0.0")]
public partial class App : System.Windows.Application {
/// <summary>
/// InitializeComponent
/// </summary>
[System.Diagnostics.DebuggerNonUserCodeAttribute()]
public void InitializeComponent() {
#line 4 "..\..\..\App.xaml"
this.StartupUri = new System.Uri("MainWindow.xaml", System.UriKind.Relative);
#line default
#line hidden
}
/// <summary>
/// Application Entry Point.
/// </summary>
[System.STAThreadAttribute()]
[System.Diagnostics.DebuggerNonUserCodeAttribute()]
public static void Main() {
WpfApplication1.App app = new WpfApplication1.App();
app.InitializeComponent();
app.Run();
}
}
}
App.g.cs
, as well. But I tried to add to Main()
and every time I would rebuild my project, it would revert to what you have, here. Tried to create my own in another class, but Project Properties only finds MyProject.App, not the other class, so can't redirect it. –
Soiree App.xaml.cs
in visual studio. Use the navigation bar > Method drop down list > select Main
(greyed out). This takes you to App.g.i.cs
. –
Sthilaire Main()
is automatically provided by the CLR and the WPF.
The C# compiler takes a command-line switch /m
which specifies the type that contains the implementation of Main()
. By convention, if no startup object is explicitly specified, the CLR will lookup any class that has a static Main()
method and will call it. (As @Marc Gravel pointed out in his comment)
In the case of WPF, the Main()
is automatically generated when App.xaml
is built and the /m switch is specified to make the C# compiler use that class as entry point. If you look at the project properties however, you'll find there's a setting for you to choose the startup object. So if you want, you can provide your own class that implements Main()
.
Note that this will put the responsibility on you to create the Application
instance and call its Run()
method to ensure that the WPF infrastructure is started properly.
/m
it doesn't care what the type is called; if you aren't explicit it just tries to find any suitable Main
method, and complains if it finds 0 or more than one. As an example, the "Hello World" sample in the language spec (§1.1) uses Hello
as the type name. –
Isomerism main()
is provided by the CLR (the runtime), it's really the compiler that generates it. –
Diley MyApp.App app = new MyApp.App();
) and call .Run()
on it, like the previous Main()
would have. Good call. Also, would have to add app.InitializeComponent();
before app.Run()
, and fortunately for us, the original InitializeComponent()
method is still there (seen in App.g.cs, so no need to add that one back!). –
Soiree Main()
is generated during compilation. You can find it in App.g.cs
(in obj/{Debug,Release}
folder).
main()
is a standard entry point for an application, but all applications are structured that way. In a XAML project, the App.XAML file specifies the entry point where it says StartupUri="MainWindow.xaml"
.
As it is stated by others, the actual main function is generated based on the contents of the XAML files in the project.
In case you removed default App.xaml and MinWindow.xaml, better to edit .csproj After adding App.xaml manually, your .csproj will be:
<Page Include ="App.xaml">
<DependentUpon>MSBuild:Compile</DependentUpon>
<SubType>Code</SubType>
</Page>
Change this to:
<ApplicationDefinition Include="App.xaml">
<Generator>MSBuild:Compile</Generator>
<SubType>Designer</SubType>
</ApplicationDefinition>
I copied files that wouldn't load in another project that was without a mainwindow into a new one and got this error.
For me it took doing the opposite approach to Andreas Kahler to fix:
After making a window file and setting the startup uri to this file i switched Page to ApplicationDefinition of App.xaml 'Build Action' property.
To clear this is error, do the following steps:
- Right-click on
App.Xaml
- Properties > Change Build Action
- From Page to > ApplicationDefinition
- Build the solution and run
It will work fine - refer to this screenshot:
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