It seems your input image is a bit different than the one you posted, since I couldn't directly collect the branch points (there were too many of them). So, to start handling your problem I considering a thinning followed by branch point detection. I also dilate them and remove from the thinned image, this guarantees that in fact there is no connection (4 or 8) between the different segments in the initial image.
f = im2bw(imread('http://i.imgur.com/yeFyF.png'), 0);
g = bwmorph(f, 'thin', 'Inf');
h = g & ~bwmorph(bwmorph(g, 'branchpoints'), 'dilate');
Since h
holds disconnected segments, the following operation collects the end points of all the segments:
u = bwmorph(h, 'endpoints');
Now to actually solve your problem I did some quick analysis on what you want to discard. Consider two distinct segments, a
and b
, in h
. We say a
and b
overlap if the end points of one is contained in the other. By contained I simply mean if the starting x point of one is smaller or equal to the other, and the ending x point is greater or equal too. In your case, the "mountain" overlaps with the segment that you wish to remove. To determine each of them you remove, consider their area. But, since these are segments, area is a meaningless term. To handle that, I connected the end points of a segment, and used as area simply the interior points. As you can clearly notice, the area of the overlapped segment at bottom is very small, so we say it is basically a line and discard it while keeping the "mountain" segment. To do this step the image u
is of fundamental importance, since with it you have a clear indication of where to start and stop tracking a contour. If you used the image h
as is , you would have trouble determining where to start and stop collecting the points of a contour (i.e., the raster order would give you incorrect overlapping indication).
To reconstruct the segment as a single one (currently you have three of them), consider the points you discarded from g
in h
, and use those that doesn't belong to the now removed bottom segment.