I expect it would break some other parse but this is not immediately springing to mind...
E.g. If I say this:
#include <stdio.h>
int main()
{
int i = 10 000;
printf("%d\n", i);
return 0;
}
My compiler says this:
ctest.c:5: error: expected ‘,’ or ‘;’ before numeric constant
I'm thinking that it would be a feature, i.e. it's easier to 'eye parse' large integers with thousands separators. I'm using a recent GCC and assuming this is the case for other compilers/parsers/lexers; whichever it is that objects.