What is "Best Practice" For Comparing Two Instances of a Reference Type?
Asked Answered
L

10

48

I came across this recently, up until now I have been happily overriding the equality operator (==) and/or Equals method in order to see if two references types actually contained the same data (i.e. two different instances that look the same).

I have been using this even more since I have been getting more in to automated testing (comparing reference/expected data against that returned).

While looking over some of the coding standards guidelines in MSDN I came across an article that advises against it. Now I understand why the article is saying this (because they are not the same instance) but it does not answer the question:

  1. What is the best way to compare two reference types?
  2. Should we implement IComparable? (I have also seen mention that this should be reserved for value types only).
  3. Is there some interface I don't know about?
  4. Should we just roll our own?!

Many Thanks ^_^

Update

Looks like I had mis-read some of the documentation (it's been a long day) and overriding Equals may be the way to go..

If you are implementing reference types, you should consider overriding the Equals method on a reference type if your type looks like a base type such as a Point, String, BigNumber, and so on. Most reference types should not overload the equality operator, even if they override Equals. However, if you are implementing a reference type that is intended to have value semantics, such as a complex number type, you should override the equality operator.

Leroy answered 19/9, 2008 at 18:7 Comment(2)
"Most reference types should not overload the equality operator, even if they override Equals"? Wow, I find that a little...um...odd. So a.Equals(b) could be true, and a==b could be false. If I want to know if the references are equal (which is rarely, honestly), I would use .ReferenceEquals(a,b), anyway. I like a==b to return the same as a.Equals(b). Is that not 'best practice'?Levigate
@FlipScript: A major problem with overriding the == operator is that it's really two operators; when it's used with types for which overrides exist, it uses the override; otherwise if the operands are reference types it's a reference-equality check. Since == is bound statically rather than virtually, even when used with generics, this behavior can cause unexpected results. In vb.net, separate operators are used for overridable equality and reference equality, avoiding such ambiguity.Confute
P
23

It looks like you're coding in C#, which has a method called Equals that your class should implement, should you want to compare two objects using some other metric than "are these two pointers (because object handles are just that, pointers) to the same memory address?".

I grabbed some sample code from here:

class TwoDPoint : System.Object
{
    public readonly int x, y;

    public TwoDPoint(int x, int y)  //constructor
    {
        this.x = x;
        this.y = y;
    }

    public override bool Equals(System.Object obj)
    {
        // If parameter is null return false.
        if (obj == null)
        {
            return false;
        }

        // If parameter cannot be cast to Point return false.
        TwoDPoint p = obj as TwoDPoint;
        if ((System.Object)p == null)
        {
            return false;
        }

        // Return true if the fields match:
        return (x == p.x) && (y == p.y);
    }

    public bool Equals(TwoDPoint p)
    {
        // If parameter is null return false:
        if ((object)p == null)
        {
            return false;
        }

        // Return true if the fields match:
        return (x == p.x) && (y == p.y);
    }

    public override int GetHashCode()
    {
        return x ^ y;
    }
}

Java has very similar mechanisms. The equals() method is part of the Object class, and your class overloads it if you want this type of functionality.

The reason overloading '==' can be a bad idea for objects is that, usually, you still want to be able to do the "are these the same pointer" comparisons. These are usually relied upon for, for instance, inserting an element into a list where no duplicates are allowed, and some of your framework stuff may not work if this operator is overloaded in a non-standard way.

Palm answered 19/9, 2008 at 18:13 Comment(3)
Good answer, thank you. I am glad you added the bit about why not to overload the equality operator.Leroy
This is actually one of the weaknesses of C#. As long as the implementor follows the guidelines, though, this isn't an issue because the semantics of == won't be changed for equal references. Still, I find myself using object.ReferenceEquals in critical situations in C# (VB has Is instead).Hodge
You shouldnt be writing the equality logic at two places. Not sure how MS got it incorrect..Corbitt
H
27

Implementing equality in .NET correctly, efficiently and without code duplication is hard. Specifically, for reference types with value semantics (i.e. immutable types that treat equvialence as equality), you should implement the System.IEquatable<T> interface, and you should implement all the different operations (Equals, GetHashCode and ==, !=).

As an example, here’s a class implementing value equality:

class Point : IEquatable<Point> {
    public int X { get; }
    public int Y { get; }

    public Point(int x = 0, int y = 0) { X = x; Y = y; }

    public bool Equals(Point other) {
        if (other is null) return false;
        return X.Equals(other.X) && Y.Equals(other.Y);
    }

    public override bool Equals(object obj) => Equals(obj as Point);

    public static bool operator ==(Point lhs, Point rhs) => object.Equals(lhs, rhs);

    public static bool operator !=(Point lhs, Point rhs) => ! (lhs == rhs);

    public override int GetHashCode() => HashCode.Combine(X, Y);
}

The only movable parts in the above code are the bolded parts: the second line in Equals(Point other) and the GetHashCode() method. The other code should remain unchanged.

For reference classes that do not represent immutable values, do not implement the operators == and !=. Instead, use their default meaning, which is to compare object identity.

The code intentionally equates even objects of a derived class type. Often, this might not be desirable because equality between the base class and derived classes is not well-defined. Unfortunately, .NET and the coding guidelines are not very clear here. The code that Resharper creates, posted in another answer, is susceptible to undesired behaviour in such cases because Equals(object x) and Equals(SecurableResourcePermission x) will treat this case differently.

In order to change this behaviour, an additional type check has to be inserted in the strongly-typed Equals method above:

public bool Equals(Point other) {
    if (other is null) return false;
    if (other.GetType() != GetType()) return false;
    return X.Equals(other.X) && Y.Equals(other.Y);
}
Hodge answered 19/9, 2008 at 18:27 Comment(23)
Good Answer Konrad, too good for this question really (i.e. I only really need the equality side of things)! Nice answer though, +1 from me. :)Leroy
For classes, why are you overriding the equality and inequality operators to perform a reference comparison, when that functionality is provided by default by the System.Object base class?Almucantar
@Burly: I don’t. They should perform value comparison (notice the lhs.Equals(rhs) at the end)! The ReferenceEquals checks are merely a time-saver (under certain circumstances) because if two references are equal we don’t need to check for value equality as well (x == x, always).Hodge
Ahh, I missed the lhs.Equals(rhs) at the end. It is considered best practice /not/ to implement value equality on the == and != operators for reference types that are non-immutable. You should however, override them for value types. See my answer below for the source and discussion of this.Almucantar
Why do you think that Equals and == should be consistent? This goes against what the MSDN documentation states and it also creates a similar disconnect where == no longer means reference equality. This creates a similar usability issue since this behavior is uniformly provided by .NET.Almucantar
FWIW, I can certainly see where you are coming from, especially coming from the C++ world myself. However, since the MSDN documentation/guidelines explicitly recommends against what you are doing, I'm searching for a solid argument in favor of your position. Perhaps this deserves it's own question..Almucantar
+ for the snippet, excellent! A minor suggestion: Couldn't you move object.ReferenceEquals(lhs, rhs) from == to generic Equals? So that gives the speed (of course it depends, but assuming the worst case) checking of reference equality even for generic Equals method?Corbitt
@Corbitt No, we need it in ==, otherwise we would get the wrong result for ((Point) null) == ((Point) null); namely, it would return false which is an error. We could also perform the check in Equals, of course. In fact, in cases where that makes sense it should absolutely be done.Hodge
@KonradRudolph I knew moving out that code as such will produce bugs, but I'm thinking we can tweak that a bit to be error free. I did something similar in my answer. I think its better (in that regard).Corbitt
@Corbitt Yes, unfortunately my host has gone offline a few months ago and so far I haven’t been able to contact anybody to fix this. I still hope that they will react at some point.Hodge
@KonradRudolph sad, can't u upload it somewhere else?Corbitt
@Corbitt I don’t have the code any more myself, I would need to access my web space as well … :(Hodge
shouldn't Equals check for ReferenceEquals(this, other) ? in case someone does Equals(this) ? (instead of in ==)Monge
@Monge You can but it’s redundant, and probably inefficient (self equality checks are expected to be rare, and take up time, too)Hodge
thanks.. also visual studio suggests replacing (object.ReferenceEquals(other, null)) with (other is null) - is that ok ?Monge
@Monge Are you using VB? Then, yes, you can/should replace all usage of object.ReferenceEquals by the Is operator. In C#, you can’t because pattern matching is invokes Object.Equals under the hood, which, in turn calls the Equals method we’re in the process of overriding. So you’d get an infinite recursion. If Visual Studio’s gives you this advice in C# then that advice is unfortunately wrong.Hodge
yeah visual studio 2017 C#Monge
@Monge Actually never mind: I tested it and other is null works. Apparently the static Object.Equals performs its own (strictly speaking redundant!) null check on the second argument, and therefore does not end up calling our overridden Equals method (see also its documentation). So yes, do replace it as suggested by VS. But note that this will only work in C# 7.0 or later. Previous versions of C# didn’t support this usage of is.Hodge
ok great and thanks ! I posted a version of your answer aboveMonge
I think there is an edge case not covered: assume classes Base and Derived, and assume (new Derived(1)).Equals((new Derived(1)))==true then Base mybase1 = new Derived(1); Base mybase2 = new Derived(1); mybase1.Equals(mybase2) should return trueMonge
@Monge That case is covered, too. Along with every other combination of base/derived comparison. Furthermore, this works correctly (a) if only Base overrides equality comparison and implements IEquatable<Base>, as well as (b) if Derived also overrides the comparison and implements IEquatable<Derived>.Hodge
I see your edit, why did you remove the ReferenceEquals test ?Monge
Let us continue this discussion in chat.Hodge
P
23

It looks like you're coding in C#, which has a method called Equals that your class should implement, should you want to compare two objects using some other metric than "are these two pointers (because object handles are just that, pointers) to the same memory address?".

I grabbed some sample code from here:

class TwoDPoint : System.Object
{
    public readonly int x, y;

    public TwoDPoint(int x, int y)  //constructor
    {
        this.x = x;
        this.y = y;
    }

    public override bool Equals(System.Object obj)
    {
        // If parameter is null return false.
        if (obj == null)
        {
            return false;
        }

        // If parameter cannot be cast to Point return false.
        TwoDPoint p = obj as TwoDPoint;
        if ((System.Object)p == null)
        {
            return false;
        }

        // Return true if the fields match:
        return (x == p.x) && (y == p.y);
    }

    public bool Equals(TwoDPoint p)
    {
        // If parameter is null return false:
        if ((object)p == null)
        {
            return false;
        }

        // Return true if the fields match:
        return (x == p.x) && (y == p.y);
    }

    public override int GetHashCode()
    {
        return x ^ y;
    }
}

Java has very similar mechanisms. The equals() method is part of the Object class, and your class overloads it if you want this type of functionality.

The reason overloading '==' can be a bad idea for objects is that, usually, you still want to be able to do the "are these the same pointer" comparisons. These are usually relied upon for, for instance, inserting an element into a list where no duplicates are allowed, and some of your framework stuff may not work if this operator is overloaded in a non-standard way.

Palm answered 19/9, 2008 at 18:13 Comment(3)
Good answer, thank you. I am glad you added the bit about why not to overload the equality operator.Leroy
This is actually one of the weaknesses of C#. As long as the implementor follows the guidelines, though, this isn't an issue because the semantics of == won't be changed for equal references. Still, I find myself using object.ReferenceEquals in critical situations in C# (VB has Is instead).Hodge
You shouldnt be writing the equality logic at two places. Not sure how MS got it incorrect..Corbitt
A
17

Below I have summed up what you need to do when implementing IEquatable and provided the justification from the various MSDN documentation pages.


Summary

  • When testing for value equality is desired (such as when using objects in collections) you should implement the IEquatable interface, override Object.Equals, and GetHashCode for your class.
  • When testing for reference equality is desired you should use operator==,operator!= and Object.ReferenceEquals.
  • You should only override operator== and operator!= for ValueTypes and immutable reference types.

Justification

IEquatable

The System.IEquatable interface is used to compare two instances of an object for equality. The objects are compared based on the logic implemented in the class. The comparison results in a boolean value indicating if the objects are different. This is in contrast to the System.IComparable interface, which return an integer indicating how the object values are different.

The IEquatable interface declares two methods that must be overridden. The Equals method contains the implementation to perform the actual comparison and return true if the object values are equal, or false if they are not. The GetHashCode method should return a unique hash value that may be used to uniquely identify identical objects that contain different values. The type of hashing algorithm used is implementation-specific.

IEquatable.Equals Method

  • You should implement IEquatable for your objects to handle the possibility that they will be stored in an array or generic collection.
  • If you implement IEquatable you should also override the base class implementations of Object.Equals(Object) and GetHashCode so that their behavior is consistent with that of the IEquatable.Equals method

Guidelines for Overriding Equals() and Operator == (C# Programming Guide)

  • x.Equals(x) returns true.
  • x.Equals(y) returns the same value as y.Equals(x)
  • if (x.Equals(y) && y.Equals(z)) returns true, then x.Equals(z) returns true.
  • Successive invocations of x. Equals (y) return the same value as long as the objects referenced by x and y are not modified.
  • x. Equals (null) returns false (for non-nullable value types only. For more information, see Nullable Types (C# Programming Guide).)
  • The new implementation of Equals should not throw exceptions.
  • It is recommended that any class that overrides Equals also override Object.GetHashCode.
  • Is is recommended that in addition to implementing Equals(object), any class also implement Equals(type) for their own type, to enhance performance.

By default, the operator == tests for reference equality by determining whether two references indicate the same object. Therefore, reference types do not have to implement operator == in order to gain this functionality. When a type is immutable, that is, the data that is contained in the instance cannot be changed, overloading operator == to compare value equality instead of reference equality can be useful because, as immutable objects, they can be considered the same as long as they have the same value. It is not a good idea to override operator == in non-immutable types.

  • Overloaded operator == implementations should not throw exceptions.
  • Any type that overloads operator == should also overload operator !=.

== Operator (C# Reference)

  • For predefined value types, the equality operator (==) returns true if the values of its operands are equal, false otherwise.
  • For reference types other than string, == returns true if its two operands refer to the same object.
  • For the string type, == compares the values of the strings.
  • When testing for null using == comparisons within your operator== overrides, make sure you use the base object class operator. If you don't, infinite recursion will occur resulting in a stackoverflow.

Object.Equals Method (Object)

If your programming language supports operator overloading and if you choose to overload the equality operator for a given type, that type must override the Equals method. Such implementations of the Equals method must return the same results as the equality operator

The following guidelines are for implementing a value type:

  • Consider overriding Equals to gain increased performance over that provided by the default implementation of Equals on ValueType.
  • If you override Equals and the language supports operator overloading, you must overload the equality operator for your value type.

The following guidelines are for implementing a reference type:

  • Consider overriding Equals on a reference type if the semantics of the type are based on the fact that the type represents some value(s).
  • Most reference types must not overload the equality operator, even if they override Equals. However, if you are implementing a reference type that is intended to have value semantics, such as a complex number type, you must override the equality operator.

Additional Gotchas

Almucantar answered 8/4, 2009 at 16:49 Comment(1)
The use of the same name for Equals(Object) and Equals(OwnType) is perhaps unfortunate, since in many cases, because of implicit typecasts, neither Equals(OwnType) nor the == operator can define an equivalence relation. If I'd designed .net, the Object method would be named EquivalentTo, and overrides would be expected to use stricter equivalence standards. For example, I'd specify that 1.0m.EquivalentTo(1.00m) should be false, but 1.0m.Equals(1.00m) and 1.0m == 1.00m should be true since the values are numerically equal even though they are not equivalent.Confute
A
3

That article just recommends against overriding the equality operator (for reference types), not against overriding Equals. You should override Equals within your object (reference or value) if equality checks will mean something more than reference checks. If you want an interface, you can also implement IEquatable (used by generic collections). If you do implement IEquatable, however, you should also override equals, as the IEquatable remarks section states:

If you implement IEquatable<T>, you should also override the base class implementations of Object.Equals(Object) and GetHashCode so that their behavior is consistent with that of the IEquatable<T>.Equals method. If you do override Object.Equals(Object), your overridden implementation is also called in calls to the static Equals(System.Object, System.Object) method on your class. This ensures that all invocations of the Equals method return consistent results.

In regards to whether you should implement Equals and/or the equality operator:

From Implementing the Equals Method

Most reference types should not overload the equality operator, even if they override Equals.

From Guidelines for Implementing Equals and the Equality Operator (==)

Override the Equals method whenever you implement the equality operator (==), and make them do the same thing.

This only says that you need to override Equals whenever you implement the equality operator. It does not say that you need to override the equality operator when you override Equals.

Ambrogino answered 19/9, 2008 at 18:15 Comment(0)
C
2

For complex objects that will yield specific comparisons then implementing IComparable and defining the comparison in the Compare methods is a good implementation.

For example we have "Vehicle" objects where the only difference may be the registration number and we use this to compare to ensure that the expected value returned in testing is the one we want.

Canella answered 19/9, 2008 at 18:10 Comment(1)
Thanks for this, Paul. Noted on the IComparable interface although I think in this instance it will probably be overkill since I want to just check for equality.Leroy
S
1

I tend to use what Resharper automatically makes. for example, it autocreated this for one of my reference types:

public override bool Equals(object obj)
{
    if (ReferenceEquals(null, obj)) return false;
    if (ReferenceEquals(this, obj)) return true;
    return obj.GetType() == typeof(SecurableResourcePermission) && Equals((SecurableResourcePermission)obj);
}

public bool Equals(SecurableResourcePermission obj)
{
    if (ReferenceEquals(null, obj)) return false;
    if (ReferenceEquals(this, obj)) return true;
    return obj.ResourceUid == ResourceUid && Equals(obj.ActionCode, ActionCode) && Equals(obj.AllowDeny, AllowDeny);
}

public override int GetHashCode()
{
    unchecked
    {
        int result = (int)ResourceUid;
        result = (result * 397) ^ (ActionCode != null ? ActionCode.GetHashCode() : 0);
        result = (result * 397) ^ AllowDeny.GetHashCode();
        return result;
    }
}

If you want to override == and still do ref checks, you can still use Object.ReferenceEquals.

Scratchboard answered 19/9, 2008 at 18:15 Comment(1)
How do you make ReSharper make that stuff automatically?Johnathan
B
1

Microsoft appears to have changed their tune, or at least there is conflicting info about not overloading the equality operator. According to this Microsoft article titled How to: Define Value Equality for a Type:

"The == and != operators can be used with classes even if the class does not overload them. However, the default behavior is to perform a reference equality check. In a class, if you overload the Equals method, you should overload the == and != operators, but it is not required."

According to Eric Lippert in his answer to a question I asked about Minimal code for equality in C# - he says:

"The danger you run into here is that you get an == operator defined for you that does reference equality by default. You could easily end up in a situation where an overloaded Equals method does value equality and == does reference equality, and then you accidentally use reference equality on not-reference-equal things that are value-equal. This is an error-prone practice that is hard to spot by human code review.

A couple years ago I worked on a static analysis algorithm to statistically detect this situation, and we found a defect rate of about two instances per million lines of code across all codebases we studied. When considering just codebases which had somewhere overridden Equals, the defect rate was obviously considerably higher!

Moreover, consider the costs vs the risks. If you already have implementations of IComparable then writing all the operators is trivial one-liners that will not have bugs and will never be changed. It's the cheapest code you're ever going to write. If given the choice between the fixed cost of writing and testing a dozen tiny methods vs the unbounded cost of finding and fixing a hard-to-see bug where reference equality is used instead of value equality, I know which one I would pick."

The .NET Framework will not ever use == or != with any type that you write. But, the danger is what would happen if someone else does. So, if the class is for a 3rd party, then I would always provide the == and != operators. If the class is only intended to be used internally by the group, I would still probably implement the == and != operators.

I would only implement the <, <=, >, and >= operators if IComparable was implemented. IComparable should only be implemented if the type needs to support ordering - like when sorting or being used in an ordered generic container like SortedSet.

If the group or company had a policy in place to not ever implement the == and != operators - then I would of course follow that policy. If such a policy were in place, then it would be wise to enforce it with a Q/A code analysis tool that flags any occurrence of the == and != operators when used with a reference type.

Bangui answered 19/9, 2016 at 20:2 Comment(0)
C
0

I believe getting something as simple as checking objects for equality correct is a bit tricky with .NET's design.

For Struct

1) Implement IEquatable<T>. It improves performance noticeably.

2) Since you're having your own Equals now, override GetHashCode, and to be consistent with various equality checking override object.Equals as well.

3) Overloading == and != operators need not be religiously done since the compiler will warn if you unintentionally equate a struct with another with a == or !=, but its good to do so to be consistent with Equals methods.

public struct Entity : IEquatable<Entity>
{
    public bool Equals(Entity other)
    {
        throw new NotImplementedException("Your equality check here...");
    }

    public override bool Equals(object obj)
    {
        if (obj == null || !(obj is Entity))
            return false;

        return Equals((Entity)obj);
    }

    public static bool operator ==(Entity e1, Entity e2)
    {
        return e1.Equals(e2);
    }

    public static bool operator !=(Entity e1, Entity e2)
    {
        return !(e1 == e2);
    }

    public override int GetHashCode()
    {
        throw new NotImplementedException("Your lightweight hashing algorithm, consistent with Equals method, here...");
    }
}

For Class

From MS:

Most reference types should not overload the equality operator, even if they override Equals.

To me == feels like value equality, more like a syntactic sugar for Equals method. Writing a == b is much more intuitive than writing a.Equals(b). Rarely we'll need to check reference equality. In abstract levels dealing with logical representations of physical objects this is not something we would need to check. I think having different semantics for == and Equals can actually be confusing. I believe it should have been == for value equality and Equals for reference (or a better name like IsSameAs) equality in the first place. I would love to not take MS guideline seriously here, not just because it isn't natural to me, but also because overloading == doesn't do any major harm. That's unlike not overriding non-generic Equals or GetHashCode which can bite back, because framework doesn't use == anywhere but only if we ourself use it. The only real benefit I gain from not overloading == and != will be the consistency with design of the entire framework over which I have no control of. And that's indeed a big thing, so sadly I will stick to it.

With reference semantics (mutable objects)

1) Override Equals and GetHashCode.

2) Implementing IEquatable<T> isn't a must, but will be nice if you have one.

public class Entity : IEquatable<Entity>
{
    public bool Equals(Entity other)
    {
        if (ReferenceEquals(this, other))
            return true;

        if (ReferenceEquals(null, other))
            return false;

        //if your below implementation will involve objects of derived classes, then do a 
        //GetType == other.GetType comparison
        throw new NotImplementedException("Your equality check here...");
    }

    public override bool Equals(object obj)
    {
        return Equals(obj as Entity);
    }

    public override int GetHashCode()
    {
        throw new NotImplementedException("Your lightweight hashing algorithm, consistent with Equals method, here...");
    }
}

With value semantics (immutable objects)

This is the tricky part. Can get easily messed up if not taken care..

1) Override Equals and GetHashCode.

2) Overload == and != to match Equals. Make sure it works for nulls.

2) Implementing IEquatable<T> isn't a must, but will be nice if you have one.

public class Entity : IEquatable<Entity>
{
    public bool Equals(Entity other)
    {
        if (ReferenceEquals(this, other))
            return true;

        if (ReferenceEquals(null, other))
            return false;

        //if your below implementation will involve objects of derived classes, then do a 
        //GetType == other.GetType comparison
        throw new NotImplementedException("Your equality check here...");
    }

    public override bool Equals(object obj)
    {
        return Equals(obj as Entity);
    }

    public static bool operator ==(Entity e1, Entity e2)
    {
        if (ReferenceEquals(e1, null))
            return ReferenceEquals(e2, null);

        return e1.Equals(e2);
    }

    public static bool operator !=(Entity e1, Entity e2)
    {
        return !(e1 == e2);
    }

    public override int GetHashCode()
    {
        throw new NotImplementedException("Your lightweight hashing algorithm, consistent with Equals method, here...");
    }
}

Take special care to see how it should fare if your class can be inherited, in such cases you will have to determine if a base class object can be equal to a derived class object. Ideally, if no objects of derived class is used for equality checking, then a base class instance can be equal to a derived class instance and in such cases, there is no need to check Type equality in generic Equals of base class.

In general take care not to duplicate code. I could have made a generic abstract base class (IEqualizable<T> or so) as a template to allow re-use easier, but sadly in C# that stops me from deriving from additional classes.

Corbitt answered 16/12, 2012 at 20:17 Comment(1)
A major problem with overriding the == operator for reference types (due to what is IMHO a defect in the design of C#) is that in C# there are effectively two different operators, and the decision of which operator to use is made statically at compile time. With value types, it's possible to overload == so that it tests value equality in all cases the compiler will accept [4==4.0m and 4==4.0 compile and yield true, but 4.0m==4.0 won't compile]. That is not possible with reference types; given var s1="1"; var s2=1.ToString(); Object o1 = s1;, s1==s2 and o1==s1, but o1!=s2.Confute
M
0

All the answers above do not consider polymorphism, often you want derived references to use the derived Equals even when compared via a base reference. Please see the question/ discussion/ answers here - Equality and polymorphism

Monge answered 2/7, 2018 at 6:30 Comment(0)
C
0

I use IEqualityComparer or IEquatable for this

example:

Product Entity:

public class Product : IEquatable<Product>
{
    [Key]
    public int ID { get; set; }

    [Required]
    [MaxLength(50)]
    public string Name { get; set; }

    [Required]
    [MaxLength(50)]
    public string SKU { get; set; }

    [Required]
    [MaxLength(100)]
    public string Description { get; set; }

    [MaxLength(100)]
    public string? ImageKey { get; set; }

    [Precision(18, 2)]
    public decimal UnitPrice { get; set; }

    public static bool operator == (Product? x, Product? y) => x.Equals(y);
    public static bool operator != (Product? x, Product? y) => !x.Equals(y);
    public override int GetHashCode() => new EqualityComparer().GetHashCode(this);
    public bool Equals(Product? other) => new EqualityComparer().Equals(this, other);
    public override bool Equals(object? obj) => new EqualityComparer().Equals(this, obj as Product);
}

Equality Comparer for Product

public class EqualityComparer : IEqualityComparer<Product>
{
    public bool Equals(Product? x, Product? y)
    {
        if (x is null || y is null) return false;
        if (x.ID <= 0 || y.ID <= 0) return false;
        return x.ID == y.ID;
    }
    public int GetHashCode([DisallowNull] Product obj)
    {
        unchecked
        {
            return (17 * 23) + obj.ID.GetHashCode();
        }
    }
}

Use this via LinQ

products.Where(x => orderedProducts.Contains(x, new EqualityComparer())).ToList()

products.Any(orderedProduct.Equals)

you may use overloaded operators for this as well e.g. something like :

foreach (var orderedProduct in orderedProducts)
{
     foreach (var product in products)
     {
          if (product == orderedProduct)
          {
              var neededProduct = product 
          }
      }
 }

this can be achieved using a more clean way :

foreach (var orderedProduct in orderedProducts)
{
     var neededProduct = products.First(orderedProduct.Equals);
}
Coxa answered 20/3 at 9:39 Comment(0)

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