InitializeComponent
is a method defined on the interface System.Windows.Markup.IComponentConnector
and is used for loading the compiled page of a component.
See MSDN
excerpt below from this link which has more info:
IComponentConnector
is used internally by Baml2006Reader
.
Implementations of InitializeComponent
are widely observable as part of the infrastructure provided by frameworks or technologies that use XAML
combined with application and programming models. For example, whenever you look at the generated classes for XAML root elements in WPF pages and applications, you will see InitializeComponent defined in the output. That method also exists in the compiled assembly and plays a role in the WPF application model of loading the XAML UI content at XAML parse time (and I suppose hence InitializeComponent
has to be in an interface and be public so that other outside WPF related assemblies can make use of it).
To explain this further, go to the definition of InitializeComponent()
method in your (say): Window1.g.cs
class of say: WPFProject
project, and change its access from public
to private
(keep the .g.cs file open in your project otherwise the build process
overrides this file, and you won't be able to see the error)
Now, when you compile your WPF project, it throws a compile error as below:
Error 22 'WPFProject.Window1' does not implement interface member
'System.Windows.Markup.IComponentConnector.InitializeComponent()'.
'WPFProject.Window1.InitializeComponent()' cannot implement an
interface member because it is not public.
Additionally, InitializeComponent()
is marked with the [System.Diagnostics.DebuggerNonUserCodeAttribute()]
attribute so you can't step into this method while debugging.
There is another SO QA discussion, which would help you to explain more in detail