Is sizeof(bool) defined in the C++ language standard?
Asked Answered
C

4

136

I can't find an answer in the standard documentation. Does the C++ language standard require sizeof(bool) to always be 1 (for 1 byte), or is this size implementation-defined?

Cube answered 4/2, 2011 at 12:15 Comment(1)
If your code depends on bool to be 1 byte, you can check it at compile-time: static_assert(sizeof(bool) == 1, "OMG bool is big here");.Terrill
C
194

sizeof(bool) is implementation defined, and the standard puts notable emphasis on this fact.

§5.3.3/1, abridged:

sizeof(char), sizeof(signed char) and sizeof(unsigned char) are 1; the result of sizeof applied to any other fundamental type is implementation-defined. [Note: in particular, sizeof(bool) and sizeof(wchar_t) are implementation-defined.69)]

Footnote 69):

sizeof(bool) is not required to be 1.

Crassus answered 4/2, 2011 at 12:16 Comment(5)
is there a flag that i need to compile my program with, that my compiler will use only 1 byte for bool?Petronille
@Eagle: That's up to your compiler, I'm not sure. It's probably best you left it up to your compiler.Crassus
note that std::vector<bool> is optimized to a vector containing 1bit bools by the standard.Tippett
@Tippett Any reference?Landing
@Tippett is it standard really? This mentions implementation-dependenceRainfall
F
21

http://msdn.microsoft.com/en-us/library/tf4dy80a.aspx

"In Visual C++4.2, the Standard C++ header files contained a typedef that equated bool with int. In Visual C++ 5.0 and later, bool is implemented as a built-in type with a size of 1 byte. That means that for Visual C++ 4.2, a call of sizeof(bool) yields 4, while in Visual C++ 5.0 and later, the same call yields 1. This can cause memory corruption problems if you have defined structure members of type bool in Visual C++ 4.2 and are mixing object files (OBJ) and/or DLLs built with the 4.2 and 5.0 or later compilers."

Fredericafrederich answered 4/8, 2011 at 1:50 Comment(3)
You do realize that this is somewhat related to the question, but clearly not an answer, since 0xbadf00d asked about the standard, not some specific/arbitrarily selected compiler implementation, right?Guillotine
@ChristopherCreutzig It is a proof by counterexample.Selaginella
@Selaginella It's not a counterexample. There are many things in Visual C++ that are not standard-compliant.Cube
T
12

It's implementation defined. Only sizeof(char) is 1 by the standard.

Tonie answered 4/2, 2011 at 12:16 Comment(4)
pls note that the 1 in the standard can mean 4 byte. Than every type is a product of 4. So care that the standard ONLY defines char is the 1, but not defines the measurment.Tippett
1 means 8 bits or 1 byte in the standardPredacious
1 byte. The number of bits per byte is not defined by the standard (it needs to be at least 8 IIRC), but can be found in CHAR_BIT, defined in climits.Tonie
sizeof(unsigned char) and sizeof(signed char) also have to be 1 by the standardAugend
C
3

See 5.3.3 paragraph 1 :

[Note: in particular, sizeof(bool) and sizeof(wchar_t) are implementation-defined.69) ]

Cutright answered 4/2, 2011 at 12:19 Comment(0)

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